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Oliga [24]
2 years ago
12

You’re going on a plane from Alaska to Florida and you’re taking your bike. It’s the middle of the winter. You fill up your tire

s before you leave to a pressure of 4.72 atm on a day that is -3.50°C. When you arrive in FL at 42°C, you check the pressure in your tires before you ride and find the pressure to be:
Chemistry
1 answer:
12345 [234]2 years ago
8 0

Answer:

5.52atm

Explanation:

Using the pressure law formula:

P1/T1 = P2/T2

Where;

P1 = initial pressure (atm)

P2 = final pressure (atm)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question, the following information were provided;

P1 = 4.72 atm

P2 = ?

T1 = -3.50°C = -3.50 + 273 = 269.5K

T2 = 42°C = 42 + 273 = 315K

Using P1/T1 = P2/T2

4.72/269.5 = P2/315

CROSS MULTIPLY

4.72 × 315 = 269.5 × P2

1,486.8 = 269.5P2

P2 = 1,486.8 ÷ 269.5

P2 = 5.52atm

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The table below compares the radioactive decay rates of two materials. Material Original mass of material (in grams) Mass of mat
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Answer:

The half-life of Material 1 and Material 2 are equal.

step by step explanation;

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8 0
3 years ago
How did satellite tracking allow biologists to study the green sea turtle?
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<u>Answer:</u>

It helped biologists collect data on when and where turtles travel.

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4 0
2 years ago
Read 2 more answers
The half-life of gold-198 is 2.7 days. After
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Answer: 8.1 days

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant

t = age of sample

a = let initial amount of the reactant = x

a - x = amount left after decay process= \frac{x}{4} 

a) to find rate constant

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.693}{2.7days}=0.257days^{-1}

b) for completion of one fourth of reaction

t=\frac{2.303}{k}\log\frac{x}{\frac{x}{4}}

t=\frac{2.303}{0.257}\log{4}

t=8.1days

Thus after 8.1 days , one fourth of original amount will remain.

8 0
3 years ago
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