Mass of Oxygen (O₂) : = 88.16 g
<h3>Further explanation</h3>
Given
Reaction(unbalanced)
C₆H₁₄+ O₂ → CO₂ + H₂0
25 g C₆H₁₄
Required
mass of oxygen (O₂)
Solution
Balanced equation
2C₆H₁₄ + 19O₂ ⇒12 CO₂ + 14 H₂O
mol C₆H₁₄ (MW=86,18 g/mol) :
= mass : MW
= 25 g : 86.18 g/mol
= 0.29
From the equation, mol ratio of C₆H₁₄ : O₂ = 2 : 19, so mol O₂ :
= 19/2 x mol C₆H₁₄
= 19/2 x 0.29
= 2.755
Mass O₂(MW=32 g/mol) :
= 2.755 x 32
= 88.16 g
<span>Answer is 6.66 mol.
<em>Explanation:</em>
According to the
Avogadro's constant, 1 mole of substance has 6.022 × 10²³ particles.
Number of Zinc atoms = </span>4.01 x 10²⁴
Avogadro's constant = 6.022 × 10²³ mol⁻¹
Hence,
moles of Zinc = number of Zinc atoms / Avogadro's constant
= 4.01 x 10²⁴ / 6.022 × 10²³ mol⁻¹
= 6.66 mol
1) The longer the quarrying goes on the less and less recources we will have, soon leading to no more recources
V1/T1=V2/T2
(10)/(358K)=(V2)/(278)
V2=7.765363128 L
Answer:
2H2O2 + NaClO → NaClO3 + 2H2O
