1. How many moles of oxygen are made if 12.0 moles of potassium chlorate react?

What was the period of time in london called because of the cold temp

eimsori [14]

I believe the answer is Caloric Theory

8 0

3 years ago

An oxide of nitrogen contains 30.45 mass % N.

N76 [4]

An oxide of nitrogen contains 30.45 mass % N, if the molar mass is 90± 5 g/mol the molecular formula is N₂O₄.

<h3>What is molar mass?</h3>

The molar mass of a chemical compound is determined by dividing its mass by the quantity of that compound, expressed as the number of moles in the sample, measured in moles. A substance's molar mass is one of its properties. The compound's molar mass is an average over numerous samples, which frequently have different masses because of isotopes.

<h3>How to find the molecular formula?</h3>

The whole-number multiple is defined as follows.

Whole-number multiple = $\frac{molar mass (g/mol)}{empirical formula mass (g/mol)}$

The empirical formula mass is shown below.

Mw of empirical formula = Mw of N+ 2 x (Mw of O)

= 14.01 g/mol + 2 x (16.00 g/mol)

= 46.01 g/mol

With the given molar mass or the molecular formula mass, we can get the whole-number multiple for the compound.

Whole-number multiple = $\frac{90 g/mol }{46.01 g/mol}$ ≈ 2

Multiplying the subscripts of NO2 by 2, the molecular formula is N(1x2)O(2x2)= N2O4.

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5 0

2 years ago

Given the chemical equation: Fe2O3 + 3CO --> 2Fe + 3CO2

lapo4ka [179]

Answer:

The answer to your question is 160 g of Fe₂O₃

Explanation:

Data

mass of Fe = 112 g

mass of CO = in excess

mass of Fe₂O₃ = ?

Balanced chemical reaction

Fe₂O₃ + 3CO ⇒ 2Fe + 3CO₂

Process

1.- Calculate the molar mass of Fe₂O₃ and Fe

Molar mass Fe₂O₃ = (56 x 2) + (16 x 3) = 112 + 48 = 160 g

atomic mass of Fe = 56

2.- Use proportions to calculate the mass of Fe₂O₃ needed

160 g of Fe₂O₃ ------------------- 2(56) g of Fe

x g of Fe₂O₃ ------------------ 112 g of Fe

x = (112 x 160) / 2(56)

x = 17920/112

x = 160 g of Fe₂O₃

6 0

3 years ago

Match these items. 1. moles per liter of solution solute 2. spreading out Keq 3. substance being dissolved diffusion 4. general

Degger [83]

Answer:

1. moles per liter of solution - Molarity

2. spreading out - diffusion

3. substance being dissolved- solute

4. general equilibrium constant - Keq

5. the substance doing the dissolving in a solution - solvent

6. solubility product constant - Ksp

Explanation:

Number of moles of substance being dissolved in one liter of solution is defined as molarity

Solute is the substance which is dissolved and solvent is the substance into which the solute is dissolved. For example salt is solute and water is solvent.

Ksp defines the solubility product constant which indicates the equilibrium between a solid and solution and the number of ions of solid required to achieve this equilibrium.

Keq depicts the scenario where reactant and product concentrations are constant in a chemical reaction.

Hence, the correct match is

1. moles per liter of solution - Molarity

2. spreading out - diffusion

3. substance being dissolved- solute

4. general equilibrium constant - Keq

5. the substance doing the dissolving in a solution - solvent

6. solubility product constant - Ksp

8 0

3 years ago

Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia, where hydroele

weeeeeb [17]

If the coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

(a) The reaction is

2H₂O + 2e⁻ → H₂ + 2OH⁻

According to the reaction, 2 moles of electrons flow per mole of reaction,

(b) Given

T = 25°C

Change Celsius into Kelvin

T = 25°C

= (25 + 273 ) K

= 298 K

<h3>What is Ideal Gas Law ?</h3>

It is expressed as

PV = nRT

Hence ,

n = $\frac{PV}{RT}$

= $\frac{(12)(3.5.10^{6} )}{(0.082057)(298)}$

= 1.7176 ×10⁶ mole

Now, From the given reaction we can say that ,1 mole of H₂ is produced by 2 moles of electron

Hence, 1.7176 × 10⁶ mole of H₂ is produced by

= 2 × 1.7176 × 10⁶ moles of electron

= 3.435 ×10⁶ moles of electron

We know that

charge = moles of electron × F

= (3.435 ×10⁶ × 96500) C

= 3.31 × 10¹¹ C

(c) We know that,

Voltage = $\frac{energy}{charge}$ = $\frac{J}{C}$

1.44 V = $\frac{energy}{3.31 . 10^{11} }$

Energy = 1.44 V × 3.31 × 10¹¹ C

= 4.766 × 10¹¹ Joules

Thus from the above conclusion we can say that, coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

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Question : Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia countries, where hydroelectric plants produce inexpensive electric power, the H₂ can be made industrially by the electrolysis of water.

a) How many moles of electrons flow per mole of reaction ?

b) How many coulombs are needed to produce 3.53X10⁶ L of H₂ gas at 12.0 atm and 25°C.

c) If the coulombs are supplied at 1.44 V, how many joules are produced?

8 0

1 year ago