Frequency = 1/time period = 1/0.05 = 20s^-1.
The solution for this problem is through this formula:Ø = w1 t + 1/2 ã t^2
where:Ø - angular displacement w1 - initial angular velocity t - time ã - angular acceleration
128 = w1 x 4 + ½ x 4.5 x 5^2 128 = 4w1 + 56.254w1 = -128 + 56.25 4w1 = 71.75w1 = 71.75/4
w1 = 17.94 or 18 rad s^-1
w1 = wo + ãt
w1 - final angular velocity
wo - initial angular velocity
18 = 0 + 4.5t t = 4 s
(t) = 2t = 1.22 sec. I believe ...
Answer:
The 16ᵗʰ term of this sequence is 82
Step-by-step explanation:
Here,
First Term = a₁ = 9
Common Difference = (d) = 2
Now, For 16ᵗʰ term, n = 16
<em>aₙ = a + (n - 1)d</em>
a₁₆ = 7 + (16 - 1) × 2
a₁₆ = 7 + 15 × 5
a₁₆ = 7 + 75
a₁₆ = 82
Thus, The 16ᵗʰ term of this sequence is 82
<u>-TheUnknownScientist</u>
