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likoan [24]
2 years ago
5

PLS HEP WILL GIVE BRAINLIEST TO FIRST ANSWER SCIENCEE!!

Physics
1 answer:
MAVERICK [17]2 years ago
3 0

Answer:

Claim: The heart pumps more blood throughout the body when one exercises because exercise takes a lot of energy from the body.

Evidence: Heart rate went from 80 bpm to 120 bpm

Reasoning: Doing exercise takes a lot of energy to do, causing the circulatory system to have to work harder and pump more blood throughout the body in order to allow someone to be able to do a task that involves so much movement and energy.

Explanation:

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Psychophysics is a discipline in psychology that focuses solely on the identification of stimuli. T F
Rzqust [24]
Hi There,

  
This is False.
Hope this helped!
3 0
3 years ago
Read 2 more answers
The speed of the center of the earth as it orbits the sun is 107257 kmph and the absolute angular velocity of the earth about it
Sindrei [870]

Answer with Explanation:

We are given that

Speed ,v_0=107257 kmph

Angular velocity,\omega=7.292\times 10^{-5} rad/s

Radius of earth,r=6371 km=6371000 m

1 km=1000 m

Linear velocity,v=r\omega=6371000\times 7.292\times 10^{-5}=464.57 m/s

Linear velocity,v=464.57\times \frac{18}{5}=1672.46 km/h

Velocity at point A,v_A=-vi+v_0 j=-1672.46 i+107257j kmph

Velocity at point B,v_B=v_0j-vj=107257j-1672.46j=105584.54j kmph

Velocity at point C,v_C=v_0j+vi=1672.46 i+107257j kmph

Velocity at point  D,v_D=v_0j+vj=107257j+1672.46j=108929.46jkmph

3 0
3 years ago
A rope passes over a fixed sheave with both ends hanging straight down. The coefficient of friction between the rope and sheave
Oliga [24]

Answer:3.51

Explanation:

Given

Coefficient of Friction \mu =0.4

Consider a small element at an angle \theta having an angle of d\theta

Normal Force=T\times \frac{d\theta }{2}+(T+dT)\cdot \frac{d\theta }{2}

N=T\cdot d\theta

Friction f=\mu \times Normal\ Reaction

f=\mu \cdot N

and T+dT-T=f=\mu Td\theta

dT=\mu Td\theta

\frac{dT}{T}=\mu d\theta

\int_{T_2}^{T_1}\frac{dT}{T}=\int_{0}^{\pi }\mu d\theta

\frac{T_2}{T_1}=e^{\mu \pi}

\frac{T_2}{T_1}=e^{0.4\times \pi }

\frac{T_2}{T_1}==e^{1.256}

\frac{T_2}{T_1}=3.51

7 0
3 years ago
Two bodies are falling with negligible air resistance, side by side, above a horizontal plane. If one of the bodies is given an
tankabanditka [31]

Answer:4-strikes the plane at same time as the other body

Explanation:

Given

If both bodies is falling on a horizontal plane and second body is given an acceleration in horizontal direction then it does not change the time to reach the Horizontal Plate as there is no change in vertical direction.

Horizontal acceleration will give only horizontal range and horizontal velocity.

8 0
3 years ago
Read 2 more answers
Verify that the SI unit of impulse is the same as the SI unit of momentum.
lys-0071 [83]

Maybe this will help you out:

Momentum is calculate by the formula:

P = mv

Where:

P = momentum

m = mass      

v = velocity

The SI unit:

mass = kg\\ velocity = \dfrac{m}{s}

So the unit of momentum would be:

kg.\dfrac{m}{s}

Impulse is defined as the change in momentum or how much force changes momentum. It can be calculate with the formula:

I = FΔt

where:

I = impulse

F = Force

Δt = change in time

The SI unit:

F = Newtons (N) or kg.\dfrac{m}{s^{2} }

t = Seconds (s)

So the unit of impulse would be derived this way:

I = FΔt

I = kg.\dfrac{m}{s^{2} } x s

or

\dfrac{kg.m.s}{s^{2}} = \dfrac{kg.m.s}{s.s}

You can then cancel out one s each from the numerator and denominator and you'll be left with:

kg.\dfrac{m}{s}

So then:

Momentum:                             Impulse

kg.\dfrac{m}{s}                                       kg.\dfrac{m}{s}

4 0
3 years ago
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