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3 years ago

What is Law of reflection ?

Physics

1 answer:

Dmitriy789 [7]3 years ago

4 0

Answer:

"*The incident ray, the reflected ray and the normal to the reflection surface at the point of the incidence lie in the same plane.

*The angle which the incident ray makes with the normal is equal to the angle which the reflected ray makes to the same normal.

*The reflected ray and the incident ray are on the opposite sides of the normal."

Explanation:

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DENIUS [597]

Answer:

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3 years ago

A supertanker filled with oil has a total mass of 6.1 x108 kg. If the dimensions of the ship are those of a rectangular box 300

IrinaVladis [17]

Answer:

The bottom of the sea is 25 m below sea level.

Explanation:

Given data

Mass = 6.1 × $10^{8} \ kg$

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We know that Buoyant force on the tank is equal to gravity force of the tank.

$F_B = F_g$

$(\rho_{Fluid}) (g) (V_{disp}) = m g$

$(\rho_{Fluid}) (V_{disp}) = m$

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We know that

$V_{disp}$ = W × L × H

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H = 25 m

Therefore the bottom of the sea is 25 m below sea level.

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3 years ago

A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel d

Dmitry [639]

Answer:

the distance in meters traveled by a point outside the rim is 157.1 m

Explanation:

Given;

radius of the disk, r = 50 cm = 0.5 m

angular speed of the disk, ω = 100 rpm

time of motion, t = 30 s

The distance in meters traveled by a point outside the rim is calculated as follows;

$\theta = \omega t\\\\\theta = (100 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m$

Therefore, the distance in meters traveled by a point outside the rim is 157.1 m

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2 years ago

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Answer:

Explanation:

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2 years ago

Read 2 more answers