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3 years ago

Calculate kinetic energy in joules of 1500 kg car moving 29m/s

1 answer:

8 0

$Kinetic\ energy=\frac{1}{2}mass*velocity^2\\\\
Kinetic energy=\frac{1}{2}*1500*29^2\\\\ Kinetic \ energy=750*841=630750J\\\\
Kinetic \ energy\ is\ equal\ to\ 630750\ Jules.$

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The noble gases have eight valence electrons and as a result are

AURORKA [14]

The noble gases have eight valence electrons and as a result are stable.

If an atom consists of 8 valence electrons, they have a full octet, and do not need to bond, which makes them "happy".

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3 years ago

What area must the plates of a capacitor be if they have a charge of 5.7uC and an electric field of 3.1 kV/mm between them? O 0.

kirill [66]

Answer:

Area of the plates of a capacitor, A = 0.208 m²

Explanation:

It is given that,

Charge on the parallel plate capacitor, $q = 5.7\ \mu C=5.7\times 10^{-6}\ C$

Electric field, E = 3.1 kV/mm = 3100000 V/m

The electric field of a parallel plates capacitor is given by :

$E=\dfrac{q}{A\epsilon_o}$

$A=\dfrac{q}{E\epsilon_o}$

$A=\dfrac{5.7\times 10^{-6}\ C}{3100000\ V/m\times 8.85\times 10^{-12}\ F/m}$

A = 0.208 m²

So, the area of the plates of a capacitor is 0.208 m². Hence, this is the required solution.

8 0

3 years ago

Please explain your answer when you found the answer (Only question number 9)

Zinaida [17]

<h3>With a uniform acceleration of 2 m/s ²</h3>

5 0

3 years ago

Rahman drops two stones P and Q each of mass 1 kg and 2 kg simultaneously from

kolbaska11 [484]

This question involves the use of the equations of motion for vertical motion.

The time taken by the stones P and Q to reach the ground is the same, that is "2 s".

The velocity with which Q hits the ground is "20 m/s".

The time taken by the stones to reach the ground can be calculated by using the second equation of motion for the vertical motion:

$h = v_it+\frac{1}{2}gt^2$

For both the stones P and Q:

h = height = 20 m

$v_i$ = initial velocity = 0 m/s

t = time = ?

g = acceleration due to gravity = 10 m/s²

Therefore,

$20\ m = (0\ m/s)t+\frac{1}{2}(10\ m/s^2)(t)^2\\\\t = \sqrt{\frac{20\ m}{5\ m/s^2}}$

<u></u>

Hence, the time taken by both the stones to reach the ground <u>is the same</u>.

To find the final velocity of stone Q we will use the first equation of motion for the vertical motion:

$v_f=v_i+gt\\v_f = 0\ m/s+(10\ m/s^2)(2\ s)\\v_f = 20\ m/s$

Learn more about equations of motion here:

brainly.com/question/20594939?referrer=searchResults

The attached picture shows the equations of motion in the horizontal and vertical directions.

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2 years ago

A positively charged glass rod attracts object X. The net charge of object X:A.may be zero or negative.B.may be zero or positive

Damm [24]

Answer:A

Explanation:

A positively charged glass rod attracts object x. So, object x must be negatively charged or uncharged.

This occurs because opposite charges attract each other or either object x is uncharged and a negative charge is induced in it as glass rod approach the object x.

So option A is correct

8 0

3 years ago