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3 years ago

6

The noble gases have eight valence electrons and as a result are

1 answer:

AURORKA [14]3 years ago

4 0

The noble gases have eight valence electrons and as a result are stable.

If an atom consists of 8 valence electrons, they have a full octet, and do not need to bond, which makes them "happy".

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A proton is moved from a position where the electric potential is 125 V to a position where the electric potential is 275 V. The

kakasveta [241]

We determine the electric potential energy of the proton by multiplying the net electric potential to the charge of the proton. The net electric potential is the difference of the final state to the that of the initial state. So, it would be 275 - 125 = 150 V.

electric potential energy = 150 (<span>1.602 × 10-19) = 2.4x10^-17 J</span>

7 0

2 years ago

exis [7]

Answer:

$27.5\ m$

Explanation:

As we know that volume of cylinder is

$v=\pi r^{2} *h$

Where v=volume , h= height or thickness and r= radius

Here,

$v= 10 m ,\ diameter= 10, \ r=\frac{diameter}{2} \ r=\frac{10}{2}\\ r=5$

Putting these values in the previous equation , we get

$10\ = \frac{22}{7} *5 *5*h\\ 14\ =\ 110*h\\h=\frac{110}{14} \\h=\frac{55}{2} \\\\h=27.5\ m$

Therefore thickness is 27.5 m

7 0

3 years ago

2. A 5 year old child pushes with a force of 5 N to get a sumo wrestler to move, but the

Svetllana [295]

formula= W=f*d

w=work done

f=force

d=distance

w=f*d

w= 5n*0(does not budge)means does not move so distance is zero

w=5J

The work done by the children on the sumo wrestler is 5J

6 0

2 years ago

You lift a 2.0 kg book from a shelf that is 1 m from the floor. What is the potential energy with respect to floor?

sladkih [1.3K]

Potential energy = mgh
Potential energy = 2 x 9.8 x 1
Potential energy 19.6 J

8 0

2 years ago

Some enterprising physics students working on a catapult decide to have a water balloon fight in the school hallway. The ceiling

sergejj [24]

Answer:

$\alpha =54.7$ º

Explanation:

From the exercise we have our initial information

$y=3.4m\\v_{o}=10m/s\\g=-9.8m/s^2$

When the balloon gets to the ceiling its velocity at that moment is 0 m/s. Being said that we can calculate velocity at the vertical direction

$v_{y}^2=v_{oy}^2+ag(y-y_{o})$

Since $v_{y}=0$ and $y_{o}=0$

$0=v_{oy}^2-2(9.8m/s^2)(3.4m)$

$v_{oy}=\sqrt{2(9.8m/s^2)(3.4m)}=8.16m/s$

Knowing that

$v_{oy}=v_{o}sin\alpha$

$sin\alpha =\frac{v_{oy} }{v_{o} }$

$\alpha =sin^{-1}(\frac{v_{oy}}{v_{o}})=sin^{-1}(\frac{8.16m/s}{10m/s})=54.7$ º

8 0

3 years ago