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Lera25 [3.4K]
3 years ago
11

A circular flat coil that has N turns, encloses an area A, and carries a current i, has its central axis parallel to a uniform m

agnetic field B in which it is immersed. The net force on the coil is
-Zero


-NiAB


-NiB


-NiA


-iBA


Is the answer zero because the coil is placed parallel to the magnetic field?
Physics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

A. Zero

Explanation:

The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :

F = N * I * A * B * sinθ

Where θ is the angle between the normal of the enclosed area and the magnetic field.

Since the normal of the area is parallel to the magnetic field, θ = 0

Hence:

F = NIABsin0

F = 0 or Zero

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A 60 kg sprinter has a momentum of +600 kg-m/s when he crosses the finish
MakcuM [25]

Answer:

10 ms⁻¹

Explanation:

The amount of momentum that an object has is dependent upon two factors

  • mass of the moving object  
  • speed of motion

In terms of an equation,

Momentum (P) = Mass(m)×velocity(v)

                     P = m×v

                 600 = 60 × v ⇒ v = 10 ms⁻¹

3 0
3 years ago
Accelerating charges radiate electromagnetic waves. Calculate the wavelength of radiation produced by a proton of mass mp moving
Iteru [2.4K]

Explanation:

Let m_p is the mass of proton. It is moving in a circular path perpendicular to a magnetic field of magnitude B.

The magnetic force is balanced by the centripetal force acting on the proton as :

\dfrac{mv^2}{r}=qvB

r is the radius of path,

r=\dfrac{mv}{qB}

Time period is given by :

T=\dfrac{2\pi r}{v}

T=\dfrac{2\pi m_p}{qB}

Frequency of proton is given by :

f=\dfrac{1}{T}=\dfrac{qB}{2\pi m_p}

The wavelength of radiation is given by :

\lambda=\dfrac{c}{f}

\lambda=\dfrac{2\pi m_pc}{qB}

So, the wavelength of radiation produced by a proton is \dfrac{2\pi m_pc}{qB}. Hence, this is the required solution.

3 0
3 years ago
Which of the following shows the conservation of mass during cellular respiration?
otez555 [7]
C, hope this helps!!!!!!!                                                                                  

7 0
3 years ago
Read 2 more answers
Determine the capacitive reactance for a 20 uF capacitor that is across a 20 volt, 60 Hz source
aleksandr82 [10.1K]

Answer:

Capacitive reactance is 132.6 Ω.

Explanation:

It is given that,

Capacitance, C=20\ \mu F=20\times 10^{-6}\ F=2\times 10^{-5}\ F

Voltage source, V = 20 volt

Frequency of source, f = 60 Hz

We need to find the capacitive reactance. It is defined as the reactance for a capacitor. It is given by :

X_C=\dfrac{1}{2\pi fC}

X_C=\dfrac{1}{2\pi \times 60\ Hz\times 2\times 10^{-5}\ F}

X_C=132.6\ \Omega

So, the capacitive reactance of the capacitor is 132.6 Ω. Hence, this is the required solution.

4 0
3 years ago
The change in momentum experienced by a object is equivalent to the...
Papessa [141]

Answer: C (impulse acting on the object)

The momentum is defined as it is the impulse acting on the force . Change in momentum is known as Impulse. Impulse is used to increase or decrease the momentum of object.                                    

From Newtons II law

              F = m. a

                = m. v/t               <em>since a = rate of change of velocity.</em>

<em>              </em>F . t = m . v

F . t is known as impulse momentum

8 0
3 years ago
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