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Lera25 [3.4K]
3 years ago
11

A circular flat coil that has N turns, encloses an area A, and carries a current i, has its central axis parallel to a uniform m

agnetic field B in which it is immersed. The net force on the coil is
-Zero


-NiAB


-NiB


-NiA


-iBA


Is the answer zero because the coil is placed parallel to the magnetic field?
Physics
1 answer:
Aneli [31]3 years ago
4 0

Answer:

A. Zero

Explanation:

The force on a coil of N turns, enclosing an area, A and carrying a current I in the presence of a magnetic field B, is :

F = N * I * A * B * sinθ

Where θ is the angle between the normal of the enclosed area and the magnetic field.

Since the normal of the area is parallel to the magnetic field, θ = 0

Hence:

F = NIABsin0

F = 0 or Zero

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Answer:

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Explanation:

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P6: An object of mass m sits on a spring of constant k in an elevator that is accelerating upwards with acceleration a. a) In te
tankabanditka [31]

Answer:

(a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

Explanation:

Given that,

Acceleration = a

mass = m

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(a). We need to calculate the spring compressed

Using balance equation

kx-mg=ma

x=\dfrac{ma+mg}{k}....(I)

The spring compressed is \dfrac{ma+mg}{k}.

(b). If the compression is 2.5 times larger than it is when the mass sits in a still elevator,

The compression is given by

x=2.5\times x_{0}

Here, acceleration is zero

So, x=2.5\times\dfrac{mg}{k}

We need to calculate the acceleration

Put the value of x in equation (I)

2.5\times \dfrac{mg}{k}=\dfrac{ma+mg}{k}

2.5\times\dfrac{mg}{k}=\dfrac{m}{k}(a+g)

a=2.5g-g

a=1.5g

Hence, (a). The spring compressed is \dfrac{ma+mg}{k}.

(b). The acceleration is 1.5 g.

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2 years ago
What velocity must a car with a mass of 1280 kg have in order to have the same momentum as a 2230?
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Momentum = (mv). 
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Answer:

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