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Pavlova-9 [17]
3 years ago
11

How far will 20 N of force stretch a spring with a spring constant of 140 N/m?

Physics
1 answer:
densk [106]3 years ago
7 0

Answer:

0.143 m

Explanation:

The relationship between force applied on a string and stretching of the spring is given by Hooke's law:

F=kx

where

F is the force exerted on the spring

k is the spring constant of the spring

x is the stretching of the spring from its equilibrium position

In this problem, we have:

F = 20 N is the force applied on the spring

k = 140 N/m is the spring constant

Solving for x, we find how far the spring will stretch:

x=\frac{F}{k}=\frac{20}{140}=0.143 m

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6.65m/s

Explanation:

Using the equation of motion

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Get S

S = 7.8u + 1/2(9.8)(7.8)²

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A ball moves along a smooth metal surface while an identical ball moves along concrete.
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Answer:

2. The metal surface exerts less frictional force because there are fewer bumps and irregularities on it than there are on the concrete.

Explanation:

Frictional force is a force that is exerted between two surfaces in contact with each other. Frictional force always opposes the direction of relative motion of the two surfaces: for instance, for a ball moving along a surface, the force of friction exerted by the surface on the ball points opposite to the direction of motion of the ball.

The magnitude of the frictional force for a ball moving on a flat surface is given by

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The value of \mu depends on the type of surface involved. In particular, a smooth surface has a smaller value of \mu, while a rough surface will have a bigger value. In this case, we are comparing a smooth metal surface with concrete: since the metal surface has fewer bumps and irregularities than concrete, it has a smaller value of coefficient of friction, so it exerts less frictional force than concrete.

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Answer:

0.1667Hz

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after carrying out the calculation of time we can easily get frequency.

time=speed/distance

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