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d1i1m1o1n [39]
3 years ago
8

Differentiate between capital g and small g​

Physics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

Capital (G) is a universal gravitation law. and small (g) is acceleration of gravity of the each (9.8m/s^2)

Explanation:

According to the web

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A 2 kg block is pushed against a spring (k = 400 N/m), compressing it 0.3 m. When the block is released, it moves along a fricti
Kitty [74]

Answer:

2.29 \mathrm{m} \text { the block slide if the } \mathrm{u}_{\mathrm{s}}=0.4

4.58 \mathrm{m} \text { the block slide if the } \mathrm{u}_{\mathrm{k}}=0.2

Explanation:

Given values  

Mass (m) = 2kg

K = 400 N/M

Compressing it 0.3 m

<u>The law of conservation of energy</u>:

\frac{m v^{2}}{2}+\frac{k x^{2}}{2}=\text { constant }

\text { Where, } \frac{m v^{2}}{2} \text { is kinetic energy of the block. }

\frac{k \Delta l^{2}}{2} Energy of the spring deformation.

M mass of the block

x spring deformation

Therefore, if block left the spring (x = 0)

\frac{m v^{2}}{2}+0=0+\frac{k \Delta l^{2}}{2}

Where, Δl is initial spring deformation

\frac{m v^{2}}{2}=\frac{k \Delta l^{2}}{2}

\mathrm{v}^{2}=\frac{k \Delta l^{2}}{m}

\mathrm{v}=\sqrt{\frac{k}{m} \times \Delta l^{2}}

v=\sqrt{\frac{400}{2} \times(0.3)^{2}}

\mathrm{v}=\sqrt{200 \times 0.09}

<u>The law of conservation of energy</u>:

\frac{m v^{2}}{2}+m g h=\text { constant }

Where h is height

\frac{m v^{2}}{2}+0=0+m g h

\frac{m v^{2}}{2}=m g h

Cancel mass "m" each side

\mathrm{h}=\frac{v^{2}}{2 g}

Distance along incline equals

\begin{array}{ll}{\text { For friction us }} & {\left(L=\frac{h}{u_{s}}\right)} \\ {\text { For friction } u_{k}} & {\left(L=\frac{h}{u_{k}}\right)}\end{array}

\begin{array}{l}{\mathrm{u}_{\mathrm{s}}=0.4} \\ {\mathrm{U}_{\mathrm{k}}=0.2} \\ {\text { For friction } \mathrm{u}_{\mathrm{s}}}\end{array}

\begin{array}{l}{\mathrm{h}=\frac{v^{2}}{2 g u_{s}}} \\ {\mathrm{L}=\frac{4.24^{2}}{2 \times 9.8 \times 0.4}} \\ {\mathrm{L}=\frac{17.9776}{784}}\end{array}

\begin{array}{l}{L=2.29 \mathrm{m}} \\ {2.29 \mathrm{m} \text { the block slide if the } \mathrm{u}_{5}=0.4} \\ {\text { For friction } \mathrm{u}_{\mathrm{k}}} \\ {\mathrm{L}=\frac{4.24^{2}}{2 \times 9.8 \times 0.2}}\end{array}

\begin{array}{l}{L=\frac{17.9776}{3.92}} \\ {L=4.58 \mathrm{m}} \\ {4.58 \mathrm{m} \text { the block slide if the } \mathrm{u}_{5}=0.4}\end{array}

8 0
2 years ago
A 195 g glider is moving at 5.3 m/s on a frictionless air track. It then collides with a stationary 295 g glider.
lord [1]

Answer:For a perfectly elastic collision, the final velocities of the carts will each be 1/2 the velocity of the initial velocity of the moving cart. For a perfectly inelastic collision, the final velocity of the cart system will be 1/2 the initial velocity of the moving cart.

Explanation:

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3 years ago
Identify the type of electrification of the road
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Electrification is widely considered as a viable strategy for reducing the oil dependency and environmental impacts of road transportation. In pursuit of this strategy, most attention has been paid to electric cars. However, substantial, yet untapped, potentials could be realized in urban areas through the large-scale introduction of electric two-wheelers.
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3 years ago
Rony fills a bucket with water and whirls it in a vertical circle to demonstrate that the water will not spill from the bucket a
Romashka-Z-Leto [24]

Answer:

0 N, 3.49 m/s

Explanation:

Draw a free body diagram for the bucket at the top of the swing.  There are two forces acting on the bucket: weight and tension, both downwards.

If we take the sum of the forces in the radial direction, where towards the center is positive:

∑F = ma

W + T = m v² / r

The higher the velocity that Rony swings the bucket, the more tension there will be.  The slowest he can swing it is when the tension is 0.

W = m v² / r

mg = m v² / r

g = v² / r

v = √(gr)

Given that r = 1.24 m:

v = √(9.8 m/s² × 1.24 m)

v = 3.49 m/s

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3 years ago
What is the scientific meaning of energy?
JulijaS [17]

Answer:

it is B

Explanation:

8 0
2 years ago
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