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d1i1m1o1n [39]
3 years ago
8

Differentiate between capital g and small g​

Physics
1 answer:
NNADVOKAT [17]3 years ago
3 0

Answer:

Capital (G) is a universal gravitation law. and small (g) is acceleration of gravity of the each (9.8m/s^2)

Explanation:

According to the web

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Steel wire rope is used to lift a heavy object. We use a 3.1m steel wire that
kaheart [24]

Answer:

Young's modulus for the rope material is 20.8 MPa.    

 

Explanation:

The Young's modulus is given by:

E = \frac{FL_{0}}{A\Delta L}

Where:

F: is the force applied on the wire

L₀: is the initial length of the wire = 3.1 m

A: is the cross-section area of the wire

ΔL: is the change in the length = 0.17 m

The cross-section area of the wire is given by the area of a circle:

A = \pi r^{2} = \pi (\frac{0.006 m}{2})^{2} = 2.83 \cdot 10^{-5} m^{2}

Now we need to find the force applied on the wire. Since the wire is lifting an object, the force is equal to the tension of the wire as follows:

F = T_{w} = W_{o}

Where:

T_{w}: is the tension of the wire

W_{o}: is the weigh of the object = mg

m: is the mass of the object = 1700 kg

g: is the acceleration due to gravity = 9.81 m/s²

F = mg = 1700 kg*9.81 m/s^{2} = 16677 N

Hence, the Young's modulus is:

E = \frac{16677 N*0.006 m}{2.83 \cdot 10^{-5} m^{2}*0.17 m} = 20.8 MPa          

Therefore, Young's modulus for the rope material is 20.8 MPa.                

I hope it helps you!                                    

7 0
3 years ago
Describe the types of waves that are made by the music of an orchestra. For example, would the violins’ waves be fast or slow? W
EleoNora [17]

Explanation:

Interference and Beats

Interference and Beats

The Doppler Effect and Shock Waves

Boundary Behavior

Reflection, Refraction, and Diffraction

Wave interference is the phenomenon that occurs when two waves meet while traveling along with the same medium. The interference of waves causes the medium to take on a shape that results from the net effect of the two individual waves upon the particles of the medium. As mentioned in a previous unit of The Physics Classroom Tutorial, if two upward displaced pulses having the same shape meet up with one another while traveling in opposite directions along with with a medium, the medium will take on the shape of an upward displaced pulse with twice the amplitude of the two interfering pulses. This type of interference is known as constructive interference. If an upward displaced pulse and a downward displaced pulse having the same shape meet up with one another while traveling in opposite directions along with a medium, the two pulses will cancel each other's effect upon the displacement of the medium and the medium will assume the equilibrium position. This type of interference is known as destructive interference. The diagrams below show two waves - one is blue and the other is red - interfering in such a way to produce a resultant shape in a medium; the result is shown in green. In two cases (on the left and in the middle), constructive interference occurs and in the third case (on the far right, destructive interference occurs.

Now if two sound waves interfere at a given location in such a way that the compression of one wave meets up with the rarefaction of a second wave, destructive interference results. The net effect of compression (which pushes particles together) and a rarefaction (which pulls particles apart) upon the particles in a given region of the medium are to not even cause a displacement of the particles. The tendency of the compression to push particles together is canceled by the tendency of the rarefactions to pull particles apart; the particles would remain at their rest position as though there wasn't even a disturbance passing through them. This is a form of destructive interference. Now if a particular location along with the medium repeatedly experiences the interference of compression and rarefaction followed up by the interference of rarefaction and impression, then the two sound waves will continually cancel each other and no sound is heard. The absence of sound is the result of the particles remaining at rest and behaving as though there was no disturbance passing through it. Amazingly, in a situation such as this, two sound waves would combine to produce no sound. As mentioned in a previous unit, locations along with the medium where destructive interference continually occurs are known as nodes.

6 0
3 years ago
The normal force of a parked car on a level surface is 15,000 Newtons. What is the force of the car?
stira [4]

Answer:

The force of the car is 15000N.

Explanation:

The unit of force is Newtons (N), so based on the question, the force is 15000 Newtons.

3 0
3 years ago
Sound waves travel through air at a speed of 330 m/s. A whistle blast at a frequency of about 1.0 kHz lasts for 2.0 s. (a) Over
klasskru [66]

Answer:

a)   x = 660 m , b)    λ = 0.330 m , c) precision  is 0.1 cm , d)    Δf= n Δt/ t²

Explanation:

a) the speed of sound is constant, therefore we can use the relation of motion to inform the distance that the sound extends is

        v = x / t

         x = v t

         x = 330 2

         x = 660 m

b) the speed of sound is

          v = λ f

          λ = v / f

          λ = 330/1000

          λ = 0.330 m

c) a measuring tape must be used to measure the wavelength, the precision  is 0.1 cm

.d) frequency measurement is more delicate, a stopwatch should be used to measure a certain number of oscillations, and hence calculate the frequency

         .f = n / t

Therefore, if we assume that there is no error in the number of oscillations, the pressure is given by the appreciation of the stopwatch, which is maximum 0.01 s

           Δf / f = Δt / t

           Δf = Δt /t   f

           Δf= n Δt/ t²

3 0
4 years ago
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