Answer:
11 am
Step-by-step explanation:
Bus A and Bus B leave the bus depot at 9 am.
Bus A takes 30 minutes to complete its route once
Bus B takes 40 minutes to complete its route once.
We solve this finding the Lowest Common Multiple of the minutes each bus uses to complete it's route
30 = 3 × 10
40 = 4 × 10
= 3 × 4 × 10
= 120 minutes
120 minutes after 9 am is
60 minutes = 1 hour
60 minutes = 1 hour
= 2 hours.
9am + 2 hours
= 11 am.
Therefore, they be back at the bus depot together at 11 am
Answer:
There is no solution to the problem
Step-by-step explanation:
In order to find the solutions to the problem you can write the situation in an algebraic form.
You have that a number is equal to twice a smaller number plus 3. This can be written as follow:
(1)
where x is the number and y is the smaller number
Furthermore, the same number x is equal to twice the sum of the smaller number and 1, which can be written as follow:
(2)
To find the solution you equal the equation (1) with (2), and you solve for y:
You obtain an inconsistency, hence, the situation of the problem does not have solution
Answer:
7 Units.
Step-by-step explanation:
First of all, you could just count the units, but that's not really too effective. Otherwise, you could start from the coordinates of the "C" point, and see how it's at -Y = -5. Therefore, to get to the line separating the two points, you would have to subtract 5 from 5 to get to the line. Now, you look at point "A". It's Y coordinate is 2. Therefore, adding 5 and 2 together gives you 7 units.
Answer:
18
Step-by-step explanation:
Substitute 9 as y. 6(9-6). Subtract: 6(3). Multiply: 18
Answer:
If we divide twice the qualifier of Jose by 4 it results in less than 8. What is Jose's highest grade?
