Explain how materials are classified on the basis of electrical conductivity. Give two uses of these materials in day to day lif
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<u>Answer:</u> The volume of the vessel is and total internal energy is 162.0 kJ.
<u>Explanation:</u>
- To calculate the volume of water, we use the equation given by ideal gas, which is:
or,
where,
P = pressure of container = 700 kPa
V = volume of container = ? L
m = Given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000 g)
M = Molar mass of R-134a = 102.03 g/mol
R = Gas constant =
T = temperature of container =
Putting values in above equation, we get:
Converting this value into , we use the conversion factor:
So,
- To calculate the internal energy, we use the equation:
or,
where,
U = total internal energy
m = given mass of R-134a = 3.98 kg = 3980 g (Conversion factor: 1kg = 1000g)
M = molar mass of R-134a = 102.03 g/mol
R = Gas constant =
T = temperature =
Putting values in above equation, we get:
Converting this into kilo joules, we use the conversion factor:
1 kJ = 1000 J
So, 161994.6 J = 162.0 kJ
Hence, the volume of the vessel is and total internal energy is 162.0 kJ.
Answer:
Explanation:
We are given the amounts of two reactants, so this is a limiting reactant problem.
We know that we will need moles, so, lets assemble the data in one place.
2Mg + O₂ ⟶ 2MgO
n/mol: 2 5
Calculate the moles of MgO we can obtain from each reactant.
From Mg:
The molar ratio of MgO:Mg is 2:2
From O₂:
The molar ratio of MgO:O₂ is 2:1.