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3 years ago

If i have a 50 L container that holds 45 moles of gas at a temperature of 473 K, what is the pressure inside the container?

Chemistry

1 answer:

Furkat [3]3 years ago

6 0

Answer:

The pressure inside the container is 34.97 atm

Explanation:

Given:

V=50L R= 0.0821LatmK^-1mol^-1

n= 45mol T= 473k

PV=nRT

P= nRT/V

= 45mol*0.0821Latmmol^-1K^-1*473K/ 50L

=34.95atm

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If this container of liquid water was frozen into ice and then, thawed back into liquid what would the volume be?

Dmitry_Shevchenko [17]

Answer:

Explanation:

because it's is still the same amount even if you freeze it

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3 years ago

Which information should be added to the chart in order find out who ran a greater distance?

Arisa [49]

Answer:

This question is incomplete, the complete question is:

Nancy and Hiyang are training for a race. They entered some of their training notes in a chart. Which information should be added to the chart in order find out who ran a greater distance?

The answer is C). the units used to measure distance each day

Explanation:

According to the question, Nancy and Hiyang are training for a race that involves them recording the distance they ran in a chart. Distance, as a quantity, is measured using different S.I units like metres, kilometers, miles, centimeters, etc.

However, in order to accurately discover whether Nancy or Hiyang ran a greater distance as recorded in their chart, the units used to measure distance each day must be included. This is because the unit of a quantity determines how big or small it is in comparison to another. For example, 20metres is not the same as 20centimetres.

If the unit they used in measuring their distance is not included, it will be impossible to tell what is being measured, talkless of who ran a greater distance

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3 years ago

How many excess electrons must be added to an isolated spherical conductor 41.0 cmcm in diameter to produce an electric field of

alina1380 [7]

Answer:

3.65 x 10¹⁰ electrons

Explanation:

we'll apply the following equation for electric field of a point charge on a spherical conductor

$E = k \frac{q}{r^{2} }$

where E is the electric field

k is a constant of the value 8.99 x 10⁹ Nm²/C²

r is the radius of the spherical conductor

q is the total charge in the sphere

Given diameter d =41.0cm, radius r = 20.5cm = 0.205m (convert cm to m)

Electrical field E = 1250 N/C

we are asked to determine how many excess electrons must be added to the surface of the sphere to produce this electric field

$E = k \frac{q}{r^{2} }$

q = E x r²

q = 1250 N/C x 0.205m²

8.99 x 10⁹ Nm²/C²

q = 5.84 x 10⁻⁹ C

this is the total charge in the sphere

To determine the number of electrons, we can divide the charge q by the charge on an electron e (1.6 x 10⁻¹⁹C)

$n = \frac{q}{e}$

n = 5.84 x 10⁻⁹ C

1.6 x 10⁻¹⁹C

n = 3.65 x 10¹⁰ electrons

Therefore, to apply an electric field of magnitude 1250 N/C, the isolated spherical conductor must contain 3.65 x 10¹⁰ electrons

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