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amid [387]
3 years ago
8

What is the biggest star in our universe?

Physics
1 answer:
oksano4ka [1.4K]3 years ago
7 0
<span>VY Canis Majoris is the largest star ever discovered.</span>
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Which macronutrient is made up of carbon and hydrogen elements joined together in long groups called hydrocarbons?
KiRa [710]

Answer:

FATS

Explanation:

Fats are made up of carbon and hydrogen elements joined together in long groups called hydrocarbons. The simplest unit of fat is the fatty acid, of which there are two types: saturated and unsaturated.

7 0
2 years ago
You want to slide a 0.39 kg book across a table. If the coefficient of kinetic friction is .21, what force is required to move t
uranmaximum [27]
Find the force that would be required in the absence of friction first, then calculate the force of friction and add them together.  This is done because the friction force is going to have to be compensated for.  We will need that much more force than we otherwise would to achieve the desired acceleration:

F_{NoFric}=ma=0.39kg \times0.18 \frac{m}{s^2}  =0.0702N

The friction force will be given by the normal force times the coefficient of friction.  Here the normal force is just its weight, mg

F_{Fric}=0.39kg \times 9.8 \frac{m}{s^2} \times 0.21=0.803N

Now the total force required is:

0.0702N+0.803N=0.873N

5 0
2 years ago
Based on its location on the periodic table, which element is a metal?
goldfiish [28.3K]

Sodium (Na) is a Alkali metal so that's the answer

6 0
2 years ago
Read 2 more answers
Fusion and fission are both processes that involve which fundamental force? to ask? A. gravitational B. weak nuclear C. electrom
marin [14]
Fusion & Fission are both processes that involve D. Strong Nuclear Fundamental forces
"D". is the answer
5 0
3 years ago
The work function for a metal surface is 4.98 eV. What is the largest wavelength of light in nm that will produce photoelectrons
bulgar [2K]

Answer:\lambda =248.99 nm

Explanation:

Given

Work function\left ( \phi \right )=4.98\approx 1.602\times 10^{-19}\times 4.98

h=6.626\times 10^{-34} J

c=2.998\times 10^8

\phi =\frac{hc}{\lambda }

\lambda =\frac{hc}{\phi }

\lambda =\frac{6.626\times 10^{-34}\times 2.998\times 10^8}{4.98\times 1.602\times 10^{-19}}

\lambda =248.99 nm

3 0
3 years ago
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