To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.
Make sure you calculate the force of gravity on the surface using the radius of the planet.
Answer:
Canada moves south
Explanation:
In North America, winter storms usually form when an air mass of cold, dry, Canadian air moves south and interacts with a warm, moist air mass moving north from the Gulf of Mexico at a point called Front.
Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736
Explanation:
According to the Arrhenius equation,
or,
![\log (\frac{f_2}{f_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7Bf_2%7D%7Bf_1%7D%29%3D%5Cfrac%7BEa%7D%7B2.303%5Ctimes%20R%7D%5B%5Cfrac%7B1%7D%7BT_1%7D-%5Cfrac%7B1%7D%7BT_2%7D%5D)
where,
= rate constant at 525K
= rate constant at 545K
= activation energy for the reaction = 185kJ/mol= 185000J/mol (1kJ=1000J)
R = gas constant = 8.314 J/mole.K
= initial temperature = 525 K
= final temperature = 545 K
Now put all the given values in this formula, we get
![\log (\frac{f_2}{f_1})=\frac{185000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{525K}-\frac{1}{545K}]](https://tex.z-dn.net/?f=%5Clog%20%28%5Cfrac%7Bf_2%7D%7Bf_1%7D%29%3D%5Cfrac%7B185000J%2Fmol%7D%7B2.303%5Ctimes%208.314J%2Fmole.K%7D%5B%5Cfrac%7B1%7D%7B525K%7D-%5Cfrac%7B1%7D%7B545K%7D%5D)
Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736
The period (T) of a vibrating object is equal to the reciprocal of the frequency (f). Completing a number of vibrations (n) takes nT time.
t = nT = n/f = 32/256 = 1/8 = 125 ms.
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