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oee [108]
3 years ago
9

Acid compounds contain a.Oxygen B. Ion c. Hydrogen

Physics
2 answers:
valentina_108 [34]3 years ago
8 0

Answer:

c hydrogen

Explanation:

lapo4ka [179]3 years ago
6 0

The answer is Hydrogen

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What is a highland? (A) An area of high or hilly land (B) A piece of land surrounded by water on three sides (C) A large area of
Karolina [17]

Answer:

A

Explanation:

A Highland is an area of mountains.

3 0
4 years ago
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Everyone experiences a wide range of emotions, but when could they indicate a mental disorder?
Vikentia [17]

Answer:

Excessive paranoia, worry, or anxiety.

Long-lasting sadness or irritability.

Extreme changes in moods.

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Explanation:

hope it helps brainliest if right thx :)

7 0
3 years ago
Calculate the pressure exerted on the floor when an elephant who weighs 6000 N stands on one foot which has an area of 20 m2
kondor19780726 [428]

Answer:

300 Pascal

Explanation:

Given

weight or force (F) = 6000 N

area (A) = 20 m²

pressure (p) = ?

we know

the force acting normally per unit area is pressure. So

P = F / A

= 6000 / 20

= 300 Pascal

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3 0
3 years ago
A car weighs 15,000 N, and its tires are inflated to a pressure of 190 kPa.How large is the area of the car's tires that are in
Elan Coil [88]
Pressure is the force applied perpendicular to a surface divided by the area of the surface. Therefore, from the given values, we can easily calculate the area by dividing the force to the pressure. We do as follows:

Area = F / P
Area = 15000 / 190000
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Hope this answers the question. Have a nice day.
7 0
3 years ago
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parallel-plate air capacitor is made from two plates 0.070 m square, spaced 6.3 mm apart. What must the potential difference bet
Rom4ik [11]

Answer:

V = 576 V

Explanation:

Given:

- The area of the two plates A = 0.070 m^2

- The space between the two plates d = 6.3 mm

- Te energy density u = 0.037 J /m^3

Find:

- What must the potential difference between the plates V?

Solution:

- The energy density of the capacitor with capacitance C and potential difference V is given as:

                               u = 0.5*ε*E^2

- Where the Electric field strength E between capacitor plates is given by:

                               E = V / d

Hence,

                               u = 0.5*ε*(V/d)^2

Where, ε = 8.854 * 10^-12

                               V^2 = 2*u*d^2 / ε

                               V = d*sqrt ( 2*u / ε )

Plug in values:

                               V = 0.0063*sqrt ( 2 * 0.037 / (8.854 * 10^-12) )

                               V = 576 V

4 0
3 years ago
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