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Usimov [2.4K]
3 years ago
13

What is the conjugate acid of hydroxylamine??

Chemistry
1 answer:
andrey2020 [161]3 years ago
6 0
The conjugate acid of hydroxylamine it means, CHEBI:15429<span> </span><span>is conjugate acid of </span>aminooxidanide, it means CHEBI:29773. 
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Calculate the internal energy of 2 moles of argon gas (assuming ideal behavior) at 298 K. Suggest two ways to increase its inter
Dominik [7]
I hope this helps you.

5 0
3 years ago
I WILL MARK YOU BRAINLIST PLEASE HELP
tekilochka [14]

Answer:  See below

Explanation:  a.  The mass of an element is composed of:

protons:     1 amu each

neutrons:   1 amu each

electrons:   0 amu each

Only the protons and neutrons are counted in the atomic mass of an element

b.  Electrons are assigned a mass of 0.  They do have a mass, but it is exceedingly small compared to the protons and neutrons, so they are left out of the calculation of an element's mass.

c.  An element becomes unstable if the neutrons exceed the protons by a certain ratio, dependent on the element.

7 0
2 years ago
The Lyman series results from excited state hydrogen atoms transiting to
Nutka1998 [239]

Answer:

I can't draw diagrams on this web site but I can do with numbers I think. So an electron is moved from n = 1 to n = 5. I'm assuming I've interpreted the problem correctly; if not you will need to make a correction. I'm assuming that you know the electron in the n = 1 state is the ground state so the 4th exited state moves it to the n = 5 level.

n = 5 4th excited state

n = 4 3rd excited state

n = 3 2nd excited state

n = 2 1st excited state

n = 1 ground state

Here are the possible spectral lines.

n = 5 to 4, n = 5 to 3, n = 5 to 2, n = 5 to 1 or 4 lines.

n = 4 to 3, 4 to 2, 4 to 1 = 3 lines

n = 3 to 2, 3 to 1 = 2 lines

n = 2 to 1 = 1 line. Add 'em up. I get 10.

b. The Lyman series is from whatever to n = 1. Count the above that end in n = 1.

c.The E for any level is -21.8E-19 Joules/n^2

To find the E for any transition (delta E) take E for upper n and subtract from the E for the lower n and that gives you delta E for the transition.

So for n = 5 to n = 1, use -Efor 5 -(-Efor 1) = + something which I'll leave for you. You could convert that to wavelength in meters with delta E = hc/wavelength. You might want to try it for the Balmer series (n ending in n = 2). I think the red line is about 650 nm.

Explanation:

8 0
2 years ago
1 point
Elina [12.6K]

Answer:

84672 J

Explanation:

From the question given above, the following data were obtained:

Height (h) = 72 m

Combined mass (m) = 120 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

We can obtain the energy by using the following formula:

E = mgh

Where

E => is the energy.

g => is the acceleration due to gravity

m => is the mass.

h => is the height.

E = 120 × 9.8 × 72

E = 84672 J

Thus, the energy is 84672 J

6 0
3 years ago
HELP ME OUT PLEASE!!!!!!!!
34kurt

Answer:

49.979

Explanation:

4 0
2 years ago
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