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Marina86 [1]
4 years ago
13

If the products of a certain reaction are favored (i.e., the ΔG value of the reaction is negative), one would expect a significa

nt amount of product to form when the reactants are combined. Which of the choices could explain why such a reaction might produce very little product?
A. low activation energy, Ea
B. negative change in entropy, ΔS
C. high activation energy, Ea
D. positive change in enthalpy, ΔH
Chemistry
2 answers:
MA_775_DIABLO [31]4 years ago
6 0

Answer:

C. High activation Energy, Ea

Explanation:

The activation energy of a chemical reaction affects the rate at which the reaction proceeds regardless of its  ΔG value. The higher the activation energy, the slower the reaction proceeds.

This occurs primarily due to the fact that the molecules of the reacting substances have to attain an energy value which is higher than the activation energy before a reaction starts. This is so even for reactions that are termed spontaneous. Molecules can only complete the reaction once they have reached the top of the activation energy barrier.

If the activation energy is high, only a few molecules will have enough energy to reach this barrier, thus slowing down the chemical reaction.

This makes option C the correct choice.

Over [174]4 years ago
4 0

Answer:

positive H and negative S

Explanation:

For a reaction to be spontaneous, the absolute best combination is a negative Delta H and a positive Delta S. When they are both positive, the reaction is only spontaneous at higher temperatures. When they are both negative, the reaction is only spontaneous at lower temperatures. and again if a catalyst is added to the reaction, the activation energy is lowered because a lower-energy transition state is formed. The catalyst does not affect the energy of the reactants or products (and thus does not affect ΔG).

So from these discussions

Ea does not affect G value at all (whether +Ea or -Ea).

And for product to be formed the reaction should be spontaneous, where H is negative and S positive else the reaction will yield low product.

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Explanation:

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by jus dot com

6 0
3 years ago
A sample of pure alumina hydrate was obtained. A 5.000 g sample of the material was heated carefully in a vacuum oven until no m
lapo4ka [179]

Answer: The formula of the hydrated alumina is  Al_2O_3.5H_2O

Explanation:

Decomposition of hydrated alumina is given by:

Al_2O_3.xH_2O\rightarrow Al_2O_3+xH_2O&#10;

Molar mass of Al_2O_3 = 101.96 g/mol

According to stoichiometry:

(101.96+18x) g of  Al_2O_3.xH_2O decomposes to give 101.96 g of

Al_2O_3

Thus 5.000 g of   Al_2O_3.xH_2O decomposes to give=\frac {101.96}{(101.96+18x)}\times 5.000 of H_2O

But it is given 5.000 g of a sample of hydrated salt Al_2O_3.xH_2O was found to contain 2.6763 g of unhydrated salt

Thus we can equate the two equations:

\frac{101.96}{(101.96+18x)}\times 5.000=2.6763

x=5

Thus the formula of the hydrated alumina is  Al_2O_3.5H_2O

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