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icang [17]
3 years ago
15

A stone is thrown at an angle of 30 degrees above the horizontal from the top edge of a cliff with an initial speed of 12 m/s. A

stop watch measures the stone’s trajectory time from top of cliff to bottom to be 4.8s. What is the height of the cliff?
Physics
1 answer:
natta225 [31]3 years ago
5 0

v = initial velocity of launch of the stone = 12 m/s

θ = angle of the velocity from the horizontal = 30

Consider the motion of the stone along the vertical direction taking upward direction as positive and down direction as negative.

v₀ = initial velocity along vertical direction = v Sinθ = 12 Sin30 = 6 m/s

a = acceleration of the stone = - 9.8 m/s²

t = time of travel = 4.8 s

Y = vertical displacement of stone = vertical height of the cliff = ?

using the kinematics equation

Y = v₀ t + (0.5) a t²

inserting the values

Y = 6 (4.8) + (0.5) (- 9.8) (4.8)²

Y = - 84.1 m

hence the height of the cliff comes out to be 84.1 m

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In a position vs. time graph depicting the motion of two different objects, the point at which the lines intersect is where the
myrzilka [38]
I think the correct answer from the choices listed above is option A. In a position vs. time graph depicting the motion of two different objects, the point at which the lines intersect is where the objects <span>have the same position. Hope this answers the question. Have a nice day.</span>
3 0
3 years ago
The worker’s pull on the handle of the cart can best be described as a force having
777dan777 [17]

Answer:

both magnitude and direction

Explanation:

The worker's pull on the handle of the cart is best described as the force having both magnitude and direction.

  • This is a vector quantity
  • The force is channeled to move the cart in a specific direction.
  • Also, the pull on the cart can be quantified, and so it have magnitude.
  • Most physical properties either have magnitude or direction or both.

In this case, the worker is pulling the cart towards a specified direction.

Therefore, the fitting choice is both magnitude and direction.

8 0
4 years ago
An astronaut, whose mission is to go where no one has gone before, lands on a spherical planet in a distant galaxy.
NeTakaya

Answer:

M = 1.77 \times 10^{27} kg

Explanation:

As we know that the that the Astronaut dropped a stone on the surface of the planet takes 0.420 s to fall a distance of d = 1.90 m

so we will have

y = \frac{1}{2}g t^2

1.90 = \frac{1}{2}g(0.420^2)

g = 21.5 m/s^2

now we know that the acceleration due to gravity is given as

g = \frac{GM}{R^2}

so we will have

21.5 = \frac{(6.67 \times 10^{-11})M}{(7.40\times 10^7)^2}

M = 1.77 \times 10^{27} kg

7 0
3 years ago
A horse slows from a velocity of 9.5 m/s to 5.5 m/s over a distance of 32 m. Find time.
lesya [120]

Answer:

8

Explanation:

Finding time= t=change in velocity or distance/acceleration

so 32/9.5-5.5

32/4

8

6 0
4 years ago
A person is watching a boat from the top of a lighthouse. The boat is approaching the lighthouse directly. When first noticed th
ValentinkaMS [17]
There are several information's already given in the question. Based on those given information's the answer can be easily deduced. 
First angle of depression = 18°33'
                                        = [18 + (33/60)] degree
                                        = 18.55 degrees
Second angle of depression = 51°33'
                                              = [51 + (33/60)] degrees
                                              = 51.55 degrees
Height of the lighthouse = 200 feet
Then
Distance traveled by the boat from when it
was first noticed until it stopped = (200/tan 18.55) - (200/tan 51.55)
                                                   = (200/0.3356) - (200/1.2594)
                                                   = 594.95 - 158.81
                                                   = 436.14 feet
I hope the procedure is clear enough for you to understand.
7 0
3 years ago
Read 2 more answers
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