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Murljashka [212]
3 years ago
12

A student buys a 5000 Btu window air conditioner for his apartment bedroom. He monitors it for one hour on a hot day and determi

nes that it operates approximately 60 percent of the time (duty cycle 5 60 percent) to keep the room at nearly constant temperature. (a) Showing all your work and using unity conversion ratios, calculate the rate of heat transfer into the bedroom through the walls, windows, etc. in units of Btu/h and in units of kW. (b) If the energy efficiency ratio (EER) of the air conditioner is 9.0 and electricity costs 7.5 cents per kilowatt-hr, calculate how much it costs (in cents) for him to run the air conditioner for one hour.

Physics
1 answer:
pochemuha3 years ago
8 0

Explanation:

Below is an attachment containing the solution.

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It takes 6 seconds for a stone to fall to the bottom of a mine shaft. how deep is the shaft
Margaret [11]
You need the kinematic equation for distance as a function of acceleration:

d = [v(initial) *t] + 0.5a*t^{2}

where a = gravitational acceleration 9.8m/s^{2}
v(initial) = starting velocity
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if the stone started at rest then v(initial) = 0 making the equation simply 0.5a * t^{2}

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6 0
3 years ago
19) A child on a sled starts from rest at the top of a 15.0° slope. If the trip to the bottom takes 15.2 s,
sveticcg [70]

Answer: 288.8 m

Explanation:

We have the following data:

t=15.2 s is the time it takes to the child to reach the bottom of the slope

V_{o}=0 is the initial velocity (the child started from rest)

\theta=15\° is the angle of the slope

d is the length of the slope

Now, the Force exerted on the sled along the ramp is:

F=ma (1)

Where m is the mass of the sled and a its acceleration

In addition, if we draw a free body diagram of this sled, the force along the ramp will be:

F=mg sin \theta (2)

Where g=9.8 m/s^{2} is the acceleration due gravity

Then:

ma=mg sin \theta (3)

Finding a:

a=g sin \theta (4)

a=9.8 m/s^{2} sin(15\°) (5)

a=2.5 m/s^{2} (6)

Now, we will use the following kinematic equations to find d:

V=V_{o}+at (7)

V^{2}=V_{o}^{2}+2ad (8)

Where V is the final velocity

Finding V from (7):

V=at=(2.5 m/s^{2})(15.2 s) (9)

V=38 m/s (10)

Substituting (10) in (8):

(38 m/s)^{2}=2(2.5 m/s^{2})d (11)

Finding d:

d=288.8 m

6 0
3 years ago
Can someone help me please? I’m so confused
Svetradugi [14.3K]

Answer:

what do you need help with? Like which type of print each image is?

Explanation:

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