Answer:
Second order line appears at 43.33° Bragg angle.
Explanation:
When there is a scattering of x- rays from the crystal lattice and interference occurs, this is known as Bragg's law.
The Bragg's diffraction equation is :
.....(1)
Here n is order of constructive interference, λ is wavelength of x-ray beam, d is the inter spacing distance of lattice and θ is the Bragg's angle or scattering angle.
Given :
Wavelength, λ = 1.4 x 10⁻¹⁰ m
Bragg's angle, θ = 20°
Order of constructive interference, n =1
Substitute these value in equation (1).
![1\times1.4\times10^{-10} =2d\sin20](https://tex.z-dn.net/?f=1%5Ctimes1.4%5Ctimes10%5E%7B-10%7D%20%3D2d%5Csin20)
d = 2.04 x 10⁻¹⁰ m
For second order constructive interference, let the Bragg's angle be θ₁.
Substitute 2 for n, 2.04 x 10⁻¹⁰ m for d and 1.4 x 10⁻¹⁰ m for λ in equation (1).
![2\times1.4\times10^{-10} =2\times2.04\times10^{-10} \sin\theta_{1}](https://tex.z-dn.net/?f=2%5Ctimes1.4%5Ctimes10%5E%7B-10%7D%20%3D2%5Ctimes2.04%5Ctimes10%5E%7B-10%7D%20%5Csin%5Ctheta_%7B1%7D)
![\sin\theta_{1} =0.68](https://tex.z-dn.net/?f=%5Csin%5Ctheta_%7B1%7D%20%3D0.68)
<em>θ₁ </em>= 43.33°
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Explanation:
Answer:
a) KE = 888.26J
b) N = 294.5 turns
Explanation:
For the kinetic energy:
![KE = I/2*\omega_o^2](https://tex.z-dn.net/?f=KE%20%3D%20I%2F2%2A%5Comega_o%5E2)
The inertia is:
![I=m/2*R^2=0.072kg.m^2](https://tex.z-dn.net/?f=I%3Dm%2F2%2AR%5E2%3D0.072kg.m%5E2)
So, the kinetic energy will be:
![KE = 888.26J](https://tex.z-dn.net/?f=KE%20%3D%20888.26J)
Now, friction force is:
Ff = μ*N = 0.80*5N = 4N
The energy balance would be:
Kf - Ko = Wf where Kf=0; Ko = 888.26J; and Wf is the work done by friction force.
Wf = -Ff*d = -Ff*N*2*π*R where N is the amount of turns it gives.
Replacing these values into the energy balance:
0-888.26=-4*N*2*π*0.12
-888.26=-0.96*π*N
N=294.5 turns