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Salsk061 [2.6K]
3 years ago
7

Bruce buys a trampoline prices at $54. if the sales tax is 3 2/5% how much tax will bruce pay

Mathematics
1 answer:
MrRa [10]3 years ago
4 0
$1.836 round off to $1.84 tax on $54 product with tax of 3.4%
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What expressions equivalent to 25c+15 ? ( more than one answer )
grin007 [14]

Answer:

The only one that looks familiar is B sorry >-<

Step-by-step explanation:

4 0
3 years ago
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Find a solution to the following system of equations. -3x+3y=-9 -3x+y=7
V125BC [204]

Answer:

(-5, -8)

Step-by-step explanation:

-3x+3y=-9

-3x+y=7

----------------

simplify -3x+3y=-9 into x-y=3

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y=x-3

-3x+y=7

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-3x+(x-3)=7

-3x+x-3=7

-2x-3=7

-2x=7+3

-2x=10

x=10/-2=-5

y=-5-3=-8

x=-5, y=-8

3 0
3 years ago
Find the area and perimeter of the compound figure below. (6 points)
fenix001 [56]

Answer:

  • area: 27.8 square units
  • perimeter: 21.2 units

Step-by-step explanation:

The area of a compound figure is the sum of the areas of its parts. The perimeter is the sum of the lengths of all of the edges.

<h3>Area</h3>

This compound figure is conveniently divided into a semicircle of radius 2.5 and a trapezoid with bases 5 and 7, and height 3.

<u>Semicircle</u>

The area of the semicircle is half the area of a circle with the same radius. It will be ...

  A = 1/2πr²

  A = 1/2π(2.5²) = 3.125π . . . . square units

<u>Trapezoid</u>

The area of the trapezoid is given by the formula ...

  A = 1/2(b1 +b2)h

  A = (1/2)(5 +7)(3) = 18 . . . . square units

Then the total area of the figure is ...

  3.125π +18 ≈ 27.8 . . . . square units

__

Perimeter

The perimeter will be the sum of the lengths of the straight line segments and the length of the semicircular arc.

<u>Arc</u>

  The arc length is half the circumference of the circle, so is ...

  arc = 1/2(2πr) = πr = 2.5π . . . . units

<u>Diagonal segments</u>

The figure is bounded by two congruent line segments that are each the hypotenuse of a triangle 1 unit wide and 3 units high. The Pythagorean theorem tells us that length is ...

  diagonal length = √(1² +3²) = √10 . . . . units

The two diagonal sides have a total length of 2√10 units.

<u>Horizontal segments</u>

The figure is bounded by two congruent horizontal segments of length 1 unit each, and one horizontal segment of length 5 units. Their total length is ...

  horizontal length = 1 + 1 + 5 = 7 . . . . units

The total perimeter is ...

  perimeter = horizontal length + diagonal length + arc length

  7 +2√10 +2.5π ≈ 21.2 . . . . units

7 0
2 years ago
How do I solve this problem
Alex73 [517]
Find a common denominator between the two (this case it would be 18) and bring the fractions up, so 10/9 would be 20/18, and 3/2 would be 27/18. Then, multiply across, and simplify to lowest terms.
4 0
3 years ago
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System practice problems
nydimaria [60]

Looking at the first system of equations,

16x - 10y = 10

-8x - 6y = 6

If we multiply both sides of the second equation by 2, the coefficient of x is exactly the negative of the coefficient of x in the first equation.

-8x - 6y = 6

⇒   2 (-8x - 6y) = 2 (6)

⇒   -16x - 12y = 12

By combining this new equation with the first one, we can eliminate x and solve for y :

(16x - 10y) + (-16x - 12y) = 10 + 12

⇒   -22y = 22

⇒   y = -1

Then we just solve for x by replacing y in either equation.

16x - 10y = 10

⇒   16x - 10 (-1) = 10

⇒   16x + 10 = 10

⇒   16x = 0

⇒   x = 0

The main idea behind elimination is combining the given equations in just the right amount so that one of the variables disappears. The "right amount" involves using the LCM of the coefficients of a given variable. In this example, the x-coefficients had LCM(8, 16) = 16, so we only had to scale one of the equations (the one with -8x) to cancel all the x terms.

If we wanted to eliminate y first instead, we first note that LCM(6, 10) = 30. To get 30 as a coefficient on y, in the first equation we would have multiplied by 3:

16x - 10y = 10

⇒   3 (16x - 10y) = 3 (10)

⇒   48x - 30y = 30

And in the second equation, we would have multiplied by -5 (negative so that upon combining the equations, we end up with -30y + 30y = 0):

-8x - 6y = 6

⇒   -5 (-8x - 6y) = -5 (6)

⇒   40x + 30y = -30

Now combining the two scaled equations gives

(48x - 30y) + (40x + 30y) = 30 + (-30)

⇒   88x = 0

⇒   x = 0

We then solve for y :

16x - 10y = 10

⇒   -10y = 10

⇒   y = -1

so we end up with the same solution as before.

8 0
3 years ago
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