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ELEN [110]
3 years ago
5

What is radioactivity.

Chemistry
1 answer:
Serggg [28]3 years ago
5 0
Radioactivity another name for radioactive decay. Radioactivity refers to particles emitted from nuclei as a result of nuclear instability. 
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One advantage to using nuclear power is —
yaroslaw [1]
It produces no air pollution
5 0
3 years ago
Read 2 more answers
Percent composition identifies the amount (in percent) of each element present in a compound.
bagirrra123 [75]

I believe the answer you are looking for is TRUE!

Forgive me if I am incorrect, hope I helped you out!

Have a great day.

8 0
3 years ago
when 0.863 mol acetone is dissolved in 500 g benzene, the freezing point of benzene drops 8.84°C. what is the molal freezing poi
sveticcg [70]

Answer:

  • <u>Kf = 5.12 °C/m</u>

Explanation:

<u>1) Data:</u>

a) Solute: acetone

b) Solvent: benzene

c) n (solute) = 0.863 mol

d) mass of solvent = 500 g = 0.500 Kg

e) ΔTf = 8.84 °C

f) Kf = ?

<u>2) Formulae:</u>

  • Depression of freezing point: ΔTf = m . Kf

  • Molality: m = n (solute) / kg solvent

<u>3) Solution:</u>

a) m = 0.863 mol / 0.500 kg = 1.726 m

b) Kf = ΔTf / m = 8.84°C / 1.726 m  = 5.12 °C/m ← answer

3 0
3 years ago
The mass percent of Cl⁻ in a seawater sample is determined by titrating 25.00 mL of seawater with AgNO₃ solution, causing a prec
Serga [27]

Answer:

2.5 %

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For AgNO_3 :

Molarity = 0.2850 M

Volume = 63.30 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 63.30 × 10⁻³ L

Thus, moles of AgNO_3 :

Moles=0.2850 \times {63.30\times 10^{-3}}\ moles

Moles of AgNO_3  = 0.0180405 moles

Moles of AgNO_3  = Moles of Cl^-

Thus, Moles of Cl^- = 0.0180405 moles

Molar mass of Cl^- = 35.453 g/mol

Mass = Moles * Molar mass = 0.0180405 moles * 35.453 g/mol = 0.6396 g

Volume of sea water = 25.00 mL

Density = 1.024 g/mL

Density = Mass / Volume

Mass = Density * Volume = 1.024 g/mL * 25.00 mL = 25.6 g

Mass\ \%=\frac{Mass_{Chloride ion}}{Total\ mass}\times 100

Mass\ \%=\frac{0.6396}{25.6}\times 100

<u>Mass percent of Cl⁻ = 2.5 %</u>

4 0
3 years ago
Marveldude pls repost what u said it got deleted :/
ad-work [718]

Answer:

position: one compound becomes 2 separate elements

synthesis: two seperate elements combining into 1 compound

single replacement: a separate element and compound switch a component

double displacement: two compounds switch elements

this is just kinda restating what red text said but this is simpler ig

5 0
3 years ago
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