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ad-work [718]
3 years ago
6

Two radio antennas are 120 m apart on a north-south line, and they radiate in phase at a frequency of 3.4 MHz. All radio measure

ments are made far from the antennas. If the east-west reference line passes midway between the two antennas, what is the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs?
Physics
1 answer:
chubhunter [2.5K]3 years ago
5 0

Answer:

the smallest angle from the antennas is <em>47.3°</em>

Explanation:

We first need to write the expression for the relation between the wavelength (λ) and the frequency (f) of the wave, and then solve for the wavelength.

Therefore, the relation is:

λ = c /f

where

  • c is the speed of light constant
  • λ is the wavelength
  • f is the frequency

Thus,

λ = (3 × 10⁸ m/s) / (3.4 MHz)

  = (3 × 10⁸ m/s) / (3.4 MHz)(10⁶ Hz/1 MHz)

  = 88.235 m

Therefore, the smallest angle measured (from the north of east) from the antennas for the constructive interference of the two-radio wave can be calculated as

θ = sin⁻¹(λ / d)

where

  • d is the distance between the two radio antennas

Thus,

θ = sin⁻¹(88.235 / 120)

<em>θ = 47.3 °</em>

<em></em>

Therefore, the smallest angle from the antennas, measured north of east, at which constructive interference of two radio waves occurs is <em>47.3 °</em>.

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In what fundamental way did the work of Galileo differ from his predecessors who had thought about the sky?
kompoz [17]

Answer: The correct answer is:

Galileo used instruments and experiments to show him what nature was doing, instead of relying on pure logic

Explanation:

Galileo can be considered as one of the precursors of experimentation and the scientific method. A method that doesn't rely on "common sense" and rationalization and logic, but instead is fuelled by a disposition of skepticism and rather makes claims about reality based on experimentation and empirical data shows.

Galileo differed from his predecessors because he actually used and developed instruments and method to reliable measure and observe what nature was doing, instead of relying on pure logic.

7 0
3 years ago
A wind turbine has a total input power of 2 500 kW.
Sonbull [250]

Answer:

Output power = 500 KW

Explanation:

Given the following data;

Efficiency = 20%

Input power = 2500 KW

To find the output power;

Efficiency = \frac {Out-put \; power}{In-put \; power} * 100

Substituting into the equation, we have;

LET Output power = OP

20 = \frac {OP}{2500} * 100

Cross-multiplying, we have;

20 * 2500 = OP * 100

50000 = OP * 100

OP = \frac {50000}{100}

Output power = 500 KW

6 0
3 years ago
you are building a race car. Your goal is to have a car that can go from 0 miles per hour to 80 miles per hour in 2 seconds. You
Vitek1552 [10]
<span>You want to focus on the car's acceleration.
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6 0
3 years ago
Read 2 more answers
Help<br>pls give me an honest answer ​
Thepotemich [5.8K]

Answer:

0.0025H

Explanation:

I didn't come here to be part of this all I wanted is just information for my research

8 0
3 years ago
(15 Points)
oksian1 [2.3K]

The vertical weight carried by the builder at the rear end is F = 308.1 N

<h3>Calculations and Parameters</h3>

Given that:

The weight is carried up along the plane in rotational equilibrium condition

The torque equilibrium condition can be used to solve

We can note that the torque due to the force of the rear person about the position of the front person = Torque due to the weight of the block about the position of the front person

This would lead to:

F(W*cosθ) = mgsinθ(L/2) + mgcosθ(W/2)

F(1cos20)= 197/2(3.10sin20 + 2 cos 20)

Fcos20= 289.55

F= 308.1N

Read more about vertical weight here:

brainly.com/question/15244771

#SPJ1

5 0
2 years ago
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