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3 years ago

If a force of 10 N is applied on a mass of 5 kg, what will be its acceleration in m/s^2

Physics

1 answer:

Brut [27]3 years ago

6 0

Answer:

$a=2\ m/s^2$

Explanation:

Second Newton's Law

The theory that explains the relationship between the forces applied to an object and its motion is the second Newton's law.

It states that the net force applied to an object of mass m is given by

$F_n=m.a$

Where a is the acceleration aquired by the object that will cause a change of its velocity.

In our problem, we must compute the acceleration

$\displaystyle a=\frac{F_n}{m}=\frac{10}{5}$

$\boxed{a=2\ m/s^2}$

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What is the frequency of a wave whose wavelength is 0.7m and whose velocity is 120m/s?

ANEK [815]

Answer:

f=171.43Hz

Explanation:

Wave frequency is the number of waves that pass a fixed point in a given amount of time.

The frequency formula is: f=v÷λ, where v is the velocity and λ is the wavelength.

Then replacing with the data of the problem,

f= $\frac{120\frac{m}{s} }{0.7m}$

f=171.43 $\frac{1}{s}$

f=171.43 Hz (because $\frac{1}{s} = Hz$ , 1 hertz equals 1 wave passing a fixed point in 1 second).

5 0

3 years ago

4 This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive

zubka84 [21]

Answer:at 21.6 min they were separated by 12 km

Explanation:

We can consider the next diagram

B2------15km/h------->Dock

B1 at 20km/h

So by the time B1 leaves, being B2 traveling at constant 15km/h and getting to the dock one hour later means it was at 15km from the dock, the other boat, B1 is at a distance at a given time, considering constant speed of 20km/h*t going south, where t is in hours, meanwhile from the dock the B2 is at a distance of (15km-15km/h*t), t=0, when it is 8pm.

Then we have a right triangle and the distance from boat B1 to boat B2, can be measured as the square root of (15-15*t)^2 +(20*t)^2. We are looking for a minimum, then we have to find the derivative with respect to t. This is 5*(25*t-9)/(sqrt(25*t^2-18*t+9)), this derivative is zero at t=9/25=0,36 h = 21.6 min, now to be sure it is a minimum we apply the second derivative criteria that states that if the second derivative at the given critical point is positive it means here we have a minimum, and by calculating the second derivative we find it is 720/(25 t^2 - 18 t + 9)^(3/2) that is positive at t=9/25, then we have our answer. And besides replacing the value of t we get the distance is 12 km.

3 0

3 years ago

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Lera25 [3.4K]

Answer:

Choice A

Explanation:

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3 0

2 years ago

5. A ball is sitting at rest on the floor. What will happen if a balanced force is applied to the ball? *

Leno4ka [110]

When the balanced force is applied on the ball It will roll away from the force.

Explanation:

A ball lies on the floor in rest. If the balanced force is applied to

the ball, the force will push away.

The forces would include gravity and the forces of air particles entering the ball from almost all directions.
And the ground is exercising the force and shifting away from the impact.

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3 years ago

How much tension is in a rope if it pulls a 5-kg bucket filled with water with an upward acceleration of 1m/s^2

liraira [26]

F=ma
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T = 5 + 5(9.81)
T = 54.05 N
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4 0

3 years ago