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Semmy [17]
3 years ago
13

If a force of 10 N is applied on a mass of 5 kg, what will be its acceleration in m/s^2

Physics
1 answer:
Brut [27]3 years ago
6 0

Answer:

a=2\ m/s^2

Explanation:

<u>Second Newton's Law</u>

The theory that explains the relationship between the forces applied to an object and its motion is the second Newton's law.

It states that the net force applied to an object of mass m is given by

F_n=m.a

Where a is the acceleration aquired by the object that will cause a change of its velocity.

In our problem, we must compute the acceleration

\displaystyle a=\frac{F_n}{m}=\frac{10}{5}

\boxed{a=2\ m/s^2}

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A 30kg mass is brought from the earth to the moon what is the weight on the earth
ozzi

Answer:

Solution

verified

Verified by Toppr

Given:

Mass of body = 30 kg

gravitational acceleration on the moon = 1.62 m/s

2

Weight of the body on the moon = Mass of the body×gravitational acceleration on the moon=30×1.62=48 N

8 0
2 years ago
A heavy copper ball of mass 2 kg is dropped from a fiftieth-floor apartment window. Another one with mass 1 kg is dropped immedi
STALIN [3.7K]

Answer:

C

Explanation:

Because everything on Earth falls at the same speed, the masses of the balls do not matter. Since the acceleration due to gravity is constant, their speeds will both be increasing at the same rate, and therefore the difference in speeds would remain constant until they hit the ground. Hope this helps!

5 0
3 years ago
a thundercloud whose base is 500m above the ground. The potential difference between the base of the cloud and the m ground is 2
kolezko [41]

Answer:

1.6×10⁻⁶ N.

Explanation:

From the question,

F = (V/r)q......................... Equation 1

Where F = Electric force on the raindrop, V = Potential difference between the base of the cloud and the ground, r = distance between the base of the cloud and the ground, q = the charge on a rain drop.

Given: V = 200MV = 200×10⁶ V, r = 500 m, q = 4.0×10⁻¹² C.

Substitute these values into equation 1

F = [(200×10⁶ )/500]×4.0×10⁻¹²

F = 1.6×10⁻⁶ N.

3 0
3 years ago
A black spider jumps with a velocity of 10 m/s at an angle of 30 degrees. At what time is the spider moving the slowest?
Tpy6a [65]

Answer:

right after jumping so 0s and as it falls its speed will keep increasing

Explanation:

5 0
3 years ago
A string of length 0.67 m and mass 2.0 g is held at both ends under tension. The string
ikadub [295]

Answer:

The value is \lambda = 0.335 \  m  

Explanation:

From the question we are told that

     The length of the string is  l  =  0.67 \  m

      The mass is  m  = 2.0 \  g  =  0.002 \  kg

      The frequency produced at  fourth harmonic vibration(i.e n =4 )  is  f =  700 \  Hz

  Generally the wavelength of the string is  mathematically represented as

            \lambda = \frac{ 2L }{n }

=>          \lambda = \frac{ 2 * 0.67 }{ 4 }  

=>          \lambda = 0.335 \  m  

7 0
3 years ago
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