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ddd [48]
3 years ago
15

A 61 kg person is in a head-on collision. The car's speed at impact is 14 m/s. Estimate the net force on the person if he or she

is wearing a seat belt and if the air bag deploys.
Physics
1 answer:
forsale [732]3 years ago
8 0

Explanation:

It is known that the relation between force and acceleration is as follows.

                F = -ma ............ (1)

Also,    acceleration (a) = \frac{v^{2} - u^{2}}{2s} ......... (2)

The given data is as follows.

                 v = 0,          u = 14 m/s,    s = 1

Therefore, putting the values of expression (2) into expression (1) as follows.

                F = -m \times \frac{v^{2} - u^{2}}{2s}

                   = -61 kg \times \frac{(0)^{2} - (14)^{2}}{2 \times 1}

                   = 5978 N

thus, we can conclude that net force on the person if he or she is wearing a seat belt and if the air bag deploys is 5978 N.

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A particle moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.
mrs_skeptik [129]

The particle's acceleration is 5.1 m/s²

<h3>What is Acceleration ?</h3>

Acceleration can be defined as the rate at which velocity is changing. It is a vector quantity and it is measured in m/s²

Given that a particle is moving along a straight line with constant acceleration has a velocity of 2.35 m/s at t=3.42 s, and a velocity of -8.72 m/s at t=5.59s

The given parameters are;

  • V1 = 2.35 m/s
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Acceleration a = ΔV ÷ ΔT

a = (2.35 + 8.72) / (5.59 - 3.42)

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a = 5.1 m/s²

Therefore, the particle's acceleration is 5.1 m/s²

Learn more about Acceleration here: brainly.com/question/9069726

#SPJ1

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