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ddd [48]
3 years ago
15

A 61 kg person is in a head-on collision. The car's speed at impact is 14 m/s. Estimate the net force on the person if he or she

is wearing a seat belt and if the air bag deploys.
Physics
1 answer:
forsale [732]3 years ago
8 0

Explanation:

It is known that the relation between force and acceleration is as follows.

                F = -ma ............ (1)

Also,    acceleration (a) = \frac{v^{2} - u^{2}}{2s} ......... (2)

The given data is as follows.

                 v = 0,          u = 14 m/s,    s = 1

Therefore, putting the values of expression (2) into expression (1) as follows.

                F = -m \times \frac{v^{2} - u^{2}}{2s}

                   = -61 kg \times \frac{(0)^{2} - (14)^{2}}{2 \times 1}

                   = 5978 N

thus, we can conclude that net force on the person if he or she is wearing a seat belt and if the air bag deploys is 5978 N.

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A 10-kg rock falls from a height of 8-m above the ground. What is the kinetic energy of the rock just before it hits the ground?
pishuonlain [190]

Answer: 800

Explanation:

1/2 x m x v^2 = m x g x h

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KE= 800

3 0
3 years ago
Boron coated with SiC (or Borsic) reinforced aluminum containing aligned 20 vol% fibers is an important high-temperature, lightw
Scilla [17]

Answer:

Option C is correct.

Modulus of elasticity of the composite perpendicular to the fibers = (12 × 10⁶) psi

Explanation:

For combination of materials, the properties (especially physical properties) of the resulting composite is a sum of the fractional contribution of each material thay makes up the composite.

In this composite,

The fibres = 20 vol%

Aluminium = 80 vol%

Modulus of elasticity of the composite

= [0.2 × E(fibres)] + [0.8 × E(Al)]

Modulus of elasticity of the fibers = E(fibres) = (55 × 10⁶) psi. =

Modulus of elasticity of aluminum = E(Al) = (10 × 10⁶) psi.

But modulus of elasticity of the composite perpendicular to the fibers is given in the expression.

[1 ÷ E(perpendicular)]

= [0.2 ÷ E(fibres)] + [0.8 ÷ E(Al)]

[1 ÷ E(perpendicular)]

= [0.2 ÷ (55 × 10⁶)] + [0.8 ÷ (10 × 10⁶)]

= (3.636 × 10⁻⁹) + (8.00 × 10⁻⁸)

= (8.3636 × 10⁻⁸)

E(perpendicular) = 1 ÷ (8.3636 × 10⁻⁸)

= 11,961,722.5 psi = (11.96 × 10⁶) psi

= (12 × 10⁶) psi

Hope this Helps!!!

6 0
3 years ago
State the methods of nuclear fission waste disposal and the suitability of each method.
Alexeev081 [22]
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</span>I suggest this site on this subject http://www.world-nuclear.org/information-library/nuclear-fuel-cycle/nuclear-wastes/storage-and-dispo...
5 0
4 years ago
Please help me .... ​
miss Akunina [59]

Explanation:

Orbital speed= 2pi x radius / time period

=2pi x 1.5x10^11 / 365.25

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8 0
3 years ago
How does an atom change if all of its electros are removed?
kogti [31]

The atom becomes positively charged.

EXPLANATION :

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Hence, the correct answer is that atom will be positively charged.

4 0
3 years ago
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