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ddd [48]
3 years ago
15

A 61 kg person is in a head-on collision. The car's speed at impact is 14 m/s. Estimate the net force on the person if he or she

is wearing a seat belt and if the air bag deploys.
Physics
1 answer:
forsale [732]3 years ago
8 0

Explanation:

It is known that the relation between force and acceleration is as follows.

                F = -ma ............ (1)

Also,    acceleration (a) = \frac{v^{2} - u^{2}}{2s} ......... (2)

The given data is as follows.

                 v = 0,          u = 14 m/s,    s = 1

Therefore, putting the values of expression (2) into expression (1) as follows.

                F = -m \times \frac{v^{2} - u^{2}}{2s}

                   = -61 kg \times \frac{(0)^{2} - (14)^{2}}{2 \times 1}

                   = 5978 N

thus, we can conclude that net force on the person if he or she is wearing a seat belt and if the air bag deploys is 5978 N.

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Answer:

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change in entropy

\Delta S =Cp ln(\frac{T_2}{T_1}) -R*ln(\frac{P_2}{P_1})

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\Delta S = 382.79 J kg^{-1} K^{-1}

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