Answer: a) 456.66 s ; b) 564.3 m
Explanation: The time spend to cover any distance a constant velocity is given by:
v= distance/time so t=distance/v
The slower student time is: t=780m/0.9 m/s= 866.66 s
For the faster students t=780 m/1,9 m/s= 410.52 s
Therefore the time difference is 866.66-410.52= 456.14 s
In order to calculate the distance that faster student should walk
to arrive 5,5 m before that slower student, we consider the follow expressions:
distance =vslower*time1
distance= vfaster*time 2
The time difference is 5.5 m that is equal to 330 s
replacing in the above expression we have
time 1= 627 s
time2 = 297 s
The distance traveled is 564,3 m
Answer:
= 2/3
Explanation:
The yuong modulus of a rod is defined as the relationship between the tensile strength and the strain
Y = 
let's use the subscript "o" for rod A
I = 
tells us that rod B has
A = 3 A₀
L = 2 L₀
we substitute
Y = 
Y = 
y = ⅔ 
substituting the value of Y₀
Y = ⅔ Y₀
= 2/3
They air is light and it pushes the ball around
Answer:
Diffusion is the movement of a molecule from an area where the molecule is in high concentration to an area where the molecule is in low concentration. Facilitated diffusion is the movement of a molecule from an area of high concentration to an area where the molecule is in low concentration. Osmosis is the diffusion (high to low concentration) of water through a semi-permeable membrane. Water moves from an area of high water molecule concentration (and lower solute concentration) to an area of low concentration (and higher solute concentration.
Hope this Helps!!!
Answer:
Explanation:
The equation for acceleration is
where vf is the final velocity and v0 is the initial velocity. Filling in:
so
a = 2.5 m/s/s
