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3 years ago

True or False

Physics

1 answer:

jasenka [17]3 years ago

6 0

False . accelerating means to increase but moving at a constant speed means you stay the same .

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Determine the stopping distances for a car with an initial speed of 88 km/h and human reaction time of 2.0 s for the following a

seropon [69]

Explanation:

Given that,

Initial speed of the car, u = 88 km/h = 24.44 m/s

Reaction time, t = 2 s

Distance covered during this time, $d=24.44\times 2=48.88\ m$

(a) Acceleration, $a=-4\ m/s^2$

We need to find the stopping distance, v = 0. It can be calculated using the third equation of motion as :

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{-(24.44)^2}{2\times -4}$

s = 74.66 meters

s = 74.66 + 48.88 = 123.54 meters

(b) Acceleration, $a=-8\ m/s^2$

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{-(24.44)^2}{2\times -8}$

s = 37.33 meters

s = 37.33 + 48.88 = 86.21 meters

Hence, this is the required solution.

4 0

3 years ago

Is god real??? i wanna know

NemiM [27]

In my opinion, yes the bible tell us that "For God so loved the world that he gave his one and only Son, that whoever believes in him shall not perish but have eternal life"
So my answer is yes

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3 years ago

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A certain plucked string produces a fundamental frequency of 150 hz. Which frequency is not one of the harmonics produced by tha

Irina-Kira [14]

Answer:

Some of the frequency that cannot be produced by the string includes 400Hz, 500Hz 650Hz etc...

Explanation:

Harmonics in strings are defined as the integral multiples of its fundamental frequency. This multiples are in arithmetic progression.

For example if Fo is the fundamental frequency of the string, the harmonics will be 2fo, 3fo, 4fo, 5fo... etc

If the string produces a fundamental frequency of 150Hz, some of the harmonics produced by the string will be 300Hz, 450Hz, 600Hz, 750Hz... etc

Some of the harmonics that cannot be produced include 400Hz, 500Hz 650Hz etc...

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3 years ago

What is the minimum coeffecient of static friction μmin required between the ladder and the ground so that the ladder does not s

mars1129 [50]

Answer:

$\mu = \frac{1}{2tan\theta}$

Explanation:

let the ladder is of mass "m" and standing at an angle with the ground

So here by horizontal force balance we will have

$\mu N_1 = N_2$

by vertical force balance we have

$N_1 = mg$

now by torque balance about contact point on ground we will have

$mg(\frac{L}{2}cos\theta) = N_2(L sin\theta)$

so we will have

$N_2 = \frac{mg}{2tan\theta}$

now from first equation we have

$\mu (mg) = \frac{mg}{2tan\theta}$

$\mu = \frac{1}{2tan\theta}$

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3 years ago

Which statement is TRUE about white light?

Olegator [25]

B: It contains all of the wavelengths of the visible light spectrum.
Hope this helps mate =)

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3 years ago

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