Answer:
The answer to your question is Aluminum
Explanation:
We need to warm from 22°C to 85°C
a) 45 g of water
b) 200 g of aluminum Cp = 0.905 J/cal°C
a) Water
Q = mCpΔT
Q = (45)(1)(85 - 22) = 45(63) = 2835 cal
b) Aluminum
Q = (200)(0.905)(85 - 22) = 114030 cal
You need to be able to draw dot-and-cross diagrams to show the ions in some common ionic compounds.
