1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivahew [28]
3 years ago
11

What is the Formula for the volume of an irregular object?

Chemistry
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Answer:

Multiply the length, width, and height together.

( length *, width *, height )

The answer to this is multiplication problem is the volume of the object.

Explanation:

- Do not measure the height of the entire container, just the height from one watermark to another.

I hope this helped!

You might be interested in
N2-3H2 → 2NH3
aniked [119]

Answer:

6 mols H2 are needed

Explanation:

N2 = 28.01g/mol

H2 = 2.02g/mol

\frac{2 mol N_{2} }{1} * \frac{3 mol H_{2}  }{ 1 mol N_{2} } = 6 mol H2

8 0
3 years ago
Can you help me please
irina [24]

Answer:

Concentrated solutions

7 0
3 years ago
Elements are organized on the periodic table based on their properties. Which statement correctly predicts and explains the chem
Elanso [62]

Answer is: a. Rubidium (Rb) is more reactive than strontium (Sr) because strontium atoms must lose more electrons.

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).  

Alkaline metals (group 1), in this example rubidium, have lowest ionizations energy and easy remove valence electrons (one electron), they are most reactive metals.

Earth alkaline metals (group 2), in this example strontium, have higher ionization energy than alkaline metals, because they have two valence electrons, they are less reactive.  

Rubidium electron configuration: ₃₇Rb 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s¹; one valence electron is 5s¹ orbital.

Strontium electron configuration: ₃₈Sr 1s²2s²2p⁶3s²3p⁶3d¹⁰4s²4p⁶5s²; two valence electrons is 5s² orbital.

7 0
3 years ago
Read 2 more answers
2.91 moles of aluminum are how many grams(with work)
pentagon [3]
2.91 mol Al * ( 26.982 g Al / 1 mol Al) = 78.518 grams
3 0
3 years ago
Read 2 more answers
Iron (III) oxide and hydrogen react to form iron and water, like this: Fe 03(s)+3H9)2Fe(s)+3HO) At a certain temperature, a chem
belka [17]

The question is incomplete, here is the complete question:

Iron (III) oxide and hydrogen react to form iron and water, like this:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

At a certain temperature, a chemist finds that a 8.9 L reaction vessel containing a mixture of iron(III) oxide, hydrogen, Iron, and water at equilibrium has the following composition.

Compound             Amount

  Fe₂O₃                     3.95 g

     H₂                        4.77 g

     Fe                        4.38 g

    H₂O                      2.00 g

Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits.

<u>Answer:</u> The value of equilibrium constant for given equation is 1.0\times 10^{-4}

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

  • <u>For hydrogen gas:</u>

Given mass of hydrogen gas = 4.77 g

Molar mass of hydrogen gas = 2 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of hydrogen gas}=\frac{4.77}{2\times 8.9}\\\\\text{Molarity of hydrogen gas}=0.268M

  • <u>For water:</u>

Given mass of water = 2.00 g

Molar mass of water = 18 g/mol

Volume of the solution = 8.9 L

Putting values in above expression, we get:

\text{Molarity of water}=\frac{2.00}{18\times 8.9}\\\\\text{Molarity of water}=0.0125M

For the given chemical equation:

Fe_2O_3(s)+3H_2(g)\rightarrow 2Fe(s)+3H_2O(g)

The expression of equilibrium constant for above equation follows:

K_{eq}=\frac{[H_2O]^3}{[H_2]^3}

Concentration of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

K_{c}=\frac{(0.0125)^3}{(0.268)^3}\\\\K_{c}=1.0\times 10^{-4}

Hence, the value of equilibrium constant for given equation is 1.0\times 10^{-4}

6 0
3 years ago
Other questions:
  • A 32 L samples of xenon gas at 10°C is expanded to 35 L. Calculate the final temperature.
    11·1 answer
  • A 78.0 g sample of an unknown compound contains 12.4 g of hydrogen. what is the percent by mass of hydrogen in the compound?
    11·2 answers
  • Imagine two electrons: one is close to the nucleus and one is far away. Which electron would be easier to remove from the atom a
    10·1 answer
  • What is the formula for trinitrogen nonaoxide
    8·2 answers
  • Which statement is true when a crystal is formed from many metal atoms? .A. There are no bands being formed.. B.There are many m
    11·2 answers
  • What is the definition of the fugacity coefficient for a pure component, and its condition at the ideal gas state?
    15·1 answer
  • Which option is not a way that heat can flow? (I think this is Chemistry)
    13·1 answer
  • g in the following three compounds(1,2,3) arrange their relative reactivity towards the reagent CH3Cl / AlCl3. Justify your orde
    15·1 answer
  • 4.0 moles of H2O would have what mass?
    11·2 answers
  • It's science pls help ​
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!