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likoan [24]
3 years ago
15

If the half-time of krypton-81 is 229,00 years, how much krypton-81 was present when the ice first formed

Chemistry
1 answer:
Morgarella [4.7K]3 years ago
8 0

Answer:

6.70g

Explanation:

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Compared to ultraviolet light, an electromagnetic wave that has a higher frequency will also have ________.
Nikitich [7]
  • The answer is shorter wavelength and equal speed.                        

That is, compared to ultraviolet light, an electromagnetic wave that has a higher frequency will also have shorter wavelength and equal speed.

This can be seen by the reaction given below:

 h\times \upsilon =\frac{c}{\lambda }

h= Planck's constant

c=speed of the light

 \upsilon=frquency

{\lambda }=wavelength

So, higher is the frequency, lesser is the volume while speed remains constant as c is speed of light.

6 0
3 years ago
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For the reaction ? Fe+? H2o ⇀↽? Fe3o4+? H2 , a maximum of how many grams of fe3o4 could be formed from 354 g of fe and 839 g of
Evgesh-ka [11]

The given reaction is:

3Fe + 4H2O → Fe3O4 + 4H2

Given:

Mass of Fe = 354 g

Mass of H2O = 839 g

Calculation:

Step 1 : Find the limiting reagent

Molar mass of Fe = 56 g/mol

Molar mass of H2O = 18 g/mol

# moles of Fe = mass of Fe/molar mass Fe  = 354/56 = 6.321 moles

# moles of H2O = mass of h2O/molar mass of H2O = 839/18 = 46.611 moles

Since moles of Fe is less than H2O;  Fe is the limiting reagent.

Step 2: Calculate moles of Fe3O4 formed

As per reaction stoichiometry:

3 moles of Fe form 1 mole of Fe3O4

Therefore, 6.321 moles of Fe = 6.321 * 1/ 3 = 2.107 moles of Fe3O4

Step 4: calculate the mass of Fe3O4 formed

Molar mass of Fe3O4 = 232 g/mol

# moles = 2.107 moles

Mass of Fe3O4 = moles * molar mass

= 2.107 moles * 232 g/mol = 488.8 g (489 g approx)

 


7 0
3 years ago
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If an ion had a charge of (-3), how many valence electrons could be expected
zimovet [89]

Answer:

Key Points. Ionic bonds are formed through the exchange of valence electrons between atoms, typically a metal and a nonmetal.

Explanation:

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2 years ago
How many moles are present when there are 1.00.1026 molecules of water?
liraira [26]

Answer: 1.00×10^26=1000×10^23

1000×10^23/6.022×10^23=166.05×10^23 moles of water.

HOPE IT HELPS ☺️

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Explanation:

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