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frozen [14]
2 years ago
5

The volume of gas changes from 5L to 3L, what will be the new pressure? What law did you use and why? HELP PLSSS <3!

Chemistry
1 answer:
babunello [35]2 years ago
8 0

Answer: F<em>or the volume of gas changes from 5L to 3L, what will be the new pressure? What law did you use and why</em>

<em>For example, if you want to calculate the volume of 40 moles of a gas under a pressure of 1013 hPa and at a temperature of 250 K, the result will be equal to: V = nRT/p = 40 * 8.3144598 * 250 / 101300 = 0.82 m³</em>

Explanation:

Brainerlist

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<u>Given: </u>

Radius of culvert, r = 0.5 m

Tangential acceleration of the truck, a = 3 m/s2

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In this experiment you’ll be grabbing the relationship between mass and volume you’ll be placing the volume on the X axis and th
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The mass and volume has direct proportional to each other.

<h3>What is the relationship between mass and volume?</h3>

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Which law relates to the ideal gas law?
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<u>Answer:</u> The law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

<u>Explanation:</u>

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Mathematically,

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Mathematically,

\frac{P_1}{T_1}=\frac{P_2}{T_2}

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Mathematically,

\frac{V_1}{n_1}=\frac{V_2}{n_2}

Hence, the law that related the ideal gas law is \frac{V_1}{n_1}=\frac{V_2}{n_2}

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