Answer:
1476 J
Explanation:
From the question,
Net Work done = Net force× distance moved by net force.
W' = (F-F')×d................... Equation 1
Where W' = Net work done, F = force applied, F' = Frictional force, d = distance moved.
Given: F = 150 N, F' = 37 N, d = 12 m
Substitute these values into equation 1
W' = (150-37)×12
W' = 123×12
W' = 1476 J.
hence the Net Work done by the object is 1476 J
Answer:
Explanation:
Work is a force time the distance moved in the direction of that force, time is not a variable. Provided that the 50 N forces were applied in the same direction, the work done is identical. Assuming both applied force and direction of motion are horizontal W = Fd = 50(10) = 500J.
If the reason that one was slower is because the second person applied his force at an angle, let's say 60° below the horizontal, then the work done by the second person is 50cos60(10) = 250 J
Time IS a consideration for Power, the RATE of doing work. Provided the force and motion are horizontal, the first person applied twice as much Power as the second person doing an identical amount of work in half the time.
Answer:
The Electric force and nuclear forces are in opposition to each other
Explanation:
<h2>
A N S W E R : –</h2>
Nothing happens to the brightness of the light bulbs in the parallel circuit if the power supply is capable of supplying the additional current.
Answer:
<h2>99 J</h2>
Explanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 9 × 11
We have the final answer as
<h3>99 J</h3>
Hope this helps you
