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3 years ago

How do the properties of an electromagnetic wave change as a result of increasing the period of the wave?

Physics

1 answer:

Ahat [919]3 years ago

8 0

Explanation:

All matter contains charged particles that are always moving therefore, all objects emit EM waves.

The relation between the magnetic field and electric field is

B_{max}= c E_{max}

The wavelength becomes shorter as the temperature of the material increases.

As frequency increases, wavelength becomes smaller.

Frequency is inversely proportional to the period of time so, when increasing the period of wave, frequency decreases, wavelength becomes larger.

wave number is inversely proportional to wave length.

so, increasing wavelength decrease the wave number.

1. wavelength increases.

2. B_max remains the same

3. polarization is same

4. wave number decreases

5. frequency decreases

6. E_max is also same

7. angular frequency decreases.

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We know that

1°=60'

The distance of city a from the initial ray is calculated as

x_a=3960*tan45.46°=4024.101 miles

The distance of city b from the initial ray is calculated as

x_b=3960*tan 38.86°=3190.75 miles

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4024.101-3190.75=833.345 miles

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3 years ago

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3 years ago

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gogolik [260]

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2 years ago

Based on the law of conservation of energy, which statement is false?

alexgriva [62]

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2 years ago

Show that the entire Paschen series is in the infrared part of the spectrum. To do this, you only need to calculate the shortest

mr_godi [17]

Answer and Explanation:

The computation of the shortest wavelength in the series is shown below:-

$\frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )$

Where

$\lambda$ represents wavelength

R represents Rydberg's constant

$n_f$ represents Final energy states

and $n_i$ represents initial energy states

Now Substitute is

$1.097\times 10^7\ m^{-1}\ for\ R, \infty for\ n_i,\ 3 for\ n_i,\\\\\ \frac{1}{\lambda} = R(\frac{1}{n_f^2} - \frac{1}{n_i^2} )$

now we will put the values into the above formula

$= 1.097\times 10^7 m^{-1}(\frac{1}{3^2} - \frac{1}{\infty^2} )\\\\ = 1.097\times10^7\ m^{-1} (\frac{1}{9} )$

$= 1218888.889 m^{-1}$

Now we will rewrite the answer in the term of $\lambda$

$\lambda = \frac{1}{1218888.889} m\\\\ = 0.82\times 10^{-6} m$

So, the whole Paschen series is in the part of the spectrum.

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3 years ago