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3 years ago

What is the partial pressure of radon if the total pressure is 780 torr and the

Chemistry

1 answer:

Brilliant_brown [7]3 years ago

6 0

Answer:

0.03atm

Explanation:

Given parameters:

Total pressure = 780torr

Partial pressure of water vapor = 1.0atm

Unknown:

Partial pressure of radon = ?

Solution:

A sound knowledge of Dalton's law of partial pressure will help solve this problem.

The law states that "the total pressure of a mixture of gases is equal to the sum of the partial pressures of the constituent gases".

Mathematically;

P $_{t}$ = P $_{1}$ + P $_{2}$ + P $_{n}$

Since the total pressure is 780torr, convert this to atm;

760torr = 1 atm

780torr = $\frac{780}{760}$ atm = 1.03atm

For this problem;

Total pressure = Partial pressure of radon + Partial pressure of water vapor

1.03 = Partial pressure of radon + 1.0

Partial pressure of radon = 1.03 - 1.00 = 0.03atm

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Explanation:

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1 year ago

Calculate for the following electrochemical cell at 25°C, Pt H2(g) (1.0 atm) H (0.010 M || Ag (0.020 M) Ag if E (H) - +0.000 V a

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Now we have to calculate the standard electrode potential of the cell.

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$E^o_{cell}=E^o_{[Ag^{+}/Ag]}-E^o_{[H^{+}/H_2]}$

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3 years ago

A frictionless piston cylinder device is subjected to 1.013 bar external pressure. The piston mass is 200 kg, it has an area of

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Answer:

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Explanation:

a) The ideal gas is experimenting an isocoric process and the following relationship is used:

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