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Zarrin [17]
3 years ago
7

A gas at 1.5 atm had pits ressure decreased to 0.50 atm producing a new volume of 750 ml what was its original volume

Chemistry
1 answer:
Vlada [557]3 years ago
6 0

Answer:

The original volume of the gas is 0.001 mL

Explanation:

This easy excersise can be solved by the law for gases, about pressure and volume; the volume of a gas is inversely proportional to the pressure it exerts.

We can propose the rule by this formula:

P₁  / V₁ = P₂ / V₂

We replace data given: 1.50 atm / V₁ = 0.50 atm / 750 mL

As the rule says, that volume is inversely proportional, and the pressure was decreased, volume must be lower than 750 mL.

1.5atm / (0.5 atm / 750mL) = V₁

V₁ = 0.001 mL

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Answer:

0.5ppm

Explanation:

Step 1:

Data obtained from the question.

Volume of water = 2500L

Mas of Cu = 1.25 g

Step 2:

Determination of the concentration of Cu in g/L. This is illustrated below:

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Conc. of Cu In g/L =?

Conc. g/L = Mass /volume

Conc. of Cu in g/L = 1.25/2500

Conc. of Cu in g/L = 5x10^–4 g/L

Step 3:

Conversion of the concentration of Cu in g/L to ppm. This is illustrated below

Recall:

1g/L = 1000mg/L

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Now, we know that 1mg/L is equal to 1ppm.

Therefore, 0.5mg/L is equivalent to 0.5ppm

6 0
3 years ago
PLS HELP
Juli2301 [7.4K]

Answer:

False

Explanation:

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Explanation:

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