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ehidna [41]
3 years ago
6

The electric field inside a cell membrane is 8.0 MN/C. Part A What's the force on a singly charged ion in this field?

Physics
1 answer:
dlinn [17]3 years ago
7 0

Answer:

Force on the singly charged ion will be 12.6\times 10^{-13}N

Explanation:

We have given electric field E = 8 MN/C

So electric field in N/C will be E=8MN/C=8\times 10^6N/C

It is given that ion so charge on ion will be equal to e=1.6\times 10^{-19}C

We have to find the electric force on the ion

Electric force is equal to F=qE, here q is charge and E is electric field

So force on the charge will be equal to F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N

So force on the singly charged ion will be 12.6\times 10^{-13}N

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Serhud [2]

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Explanation:

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V = 2*15 = 30 m/s

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2 years ago
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a 25 kg object is pushed with a horizontal force of 5 N esat across a table. If the force of friction is 2 N, what is the accele
Julli [10]

Answer:

Apply Newton's second law in the moving direction.

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8 0
3 years ago
A uniform plank 8.00 m in length with mass 50.0 kg is supported at two points located 1.00 m and 5.00 m, respectively, from the
andreev551 [17]

To solve the problem it is necessary to use Newton's second law and statistical equilibrium equations.

According to Newton's second law we have to

F = mg

where,

m= mass

g = gravitational acceleration

For the balance to break, there must be a mass M located at the right end.

We will define the mass m as the mass of the body, located in an equidistant center of the corners equal to 4m.

In this way, applying the static equilibrium equations, we have to sum up torques at point B,

\sum \tau = 0

Regarding the forces we have,

3Mg-1mg=0

Re-arrange to find M,

M = \frac{m}{3}

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Therefore the maximum additional mass you could place on the right hand end of the plank and have the plank still be at rest is 16.67Kg

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3 years ago
If revenue is $3,000 and operating expenses are $4,000, cash flow equals _____. -$1,000 $1,000 -$7,000 $7,000
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Answer:

-$1,000

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$3000 - $4000

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