Question

The electric field inside a cell membrane is 8.0 MN/C. Part A What's the force on a singly charged ion in this field?

Answer 1

Answer:

Force on the singly charged ion will be $12.6\times 10^{-13}N$

Explanation:

We have given electric field E = 8 MN/C

So electric field in N/C will be $E=8MN/C=8\times 10^6N/C$

It is given that ion so charge on ion will be equal to $e=1.6\times 10^{-19}C$

We have to find the electric force on the ion

Electric force is equal to $F=qE$, here q is charge and E is electric field

So force on the charge will be equal to $F=8\times 10^6\times 1.6\times 10^{-19}=12.6\times 10^{-13}N$

So force on the singly charged ion will be $12.6\times 10^{-13}N$