A student pushes on a 5 kg box with a force of 20 N forward. The force of sliding friction
1 answer:
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Answer:
The thickness is
Explanation:
From the question we are told that
The wavelength is
The first order of the dark fringe is
The second order of dark fringe considered is
Generally the condition for destructive interference is mathematically represented as
Here y is the path difference between the central maxima(i.e the origin) and any dark fringe
So the path difference between the 16th dark fringe and the 6th dark fringe is mathematically represented as
=>
=>
=>
Answer:
Bulk modulus = 1.35 × Pa
Explanation:
given data
density = 1400 kg/m³
frequency = 370 Hz
wavelength = 8.40 m
solution
we get here bulk modulus of the liquid that is
we know Bulk Modulus = ...............
here is density i.e 1400 kg/m³
and v is = frequency × wavelength
v = 370 × 8.40 = 3108 m/s
so here bulk modulus will be as
Bulk modulus = 3108² × 1400
Bulk modulus = 1.35 × Pa