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tensa zangetsu [6.8K]

3 years ago

5

A very long solenoid with a circular cross section and radius r1= 1.30 cm with ns= 260 turns/cm lies inside a short coil of radi

us r2= 4.60 cm and Nc= 23 turns. If the current in the solenoid is ramped at a constant rate from zero to Is= 1.90 A over a time interval of 88.0 ms, what is the magnitude of the emf in the outer coil while the current in the solenoid is changing?

1 answer:

allochka39001 [22]3 years ago

5 0

Answer:

0.00851 volts

Explanation:

radius r1= 1.30 cm with ns= 260 turns/cm

radius r2= 4.60 cm and Nc= 23 turns

constant rate from zero to Is= 1.90 A

time interval of 88.0 ms

Area of the solenoid

$A_1=\pi*r_1^2$

$=\pi*0.013^2$

$A_1=5.31*10^-^4 m^2$

Mututal Inductance

M=uo*n*N*A1

$M=(4\pi*10^-^7)*23*(260*10^2)*(5.31*10^-^4)$

$M=3.99*10^-^4 H$

a)

EMF induced in the outer coil

E=M(dIs/dt)

$E=(3.99*10^-^4)*(1.9/88*10^-^3)$

$E=0.00861 Volts$

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From the question we are told that

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The magnitude of the second charge is $q_2 = -2.00nC = -2.00*10^{-9}C$

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The force acting on the third charge due to the first and second charge is mathematically represented as

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Substituting values

$F_{31 +32} = \frac{9 *10^9 * 6 *10^{-9} * 5*10^{-9} }{(5*10^{-2}) ^3} * (4i + 3j ) *10^{-2} \\ \ + \ \ \ \ \ \ \ \ \ \frac{9 *10^9 * 6 *10^{-9} * -2*10^{-9} }{(5*10^{-2}) ^3} * (4i + 3j ) *10^{-2}$

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