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cluponka [151]
3 years ago
12

A cell phone manufacturer uses a trendy celebrity to advertise its product to teenagers. The company is relying on the route to

persuasion.
Physics
1 answer:
alina1380 [7]3 years ago
8 0

Answer:

ya ik

Explanation:

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Answer:

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Explanation:

I hope you get a good grade!

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2 years ago
Rank the five terrestrial worlds in order of size from smallest to largest: Group of answer choices Mercury, Venus, Earth, Moon,
dimaraw [331]

Answer: Moon, Mercury, Mars, Venus, Earth

Explanation:

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2 years ago
At a certain instant, the speedometer of the car indicates 80 km/h.
Scorpion4ik [409]

Answer:

  • <em>It</em><em> </em><em>tells</em><em> </em><em>the</em><em> </em><em>speed</em><em> </em><em>of</em><em> </em><em>car</em><em>.</em><em> </em><em>At</em><em> </em><em>this</em><em> </em><em>time</em><em> </em><em>the</em><em> </em><em>speed</em><em> </em><em>of</em><em> </em><em>car</em><em> </em><em>is</em><em> </em><em>8</em><em>0</em><em>k</em><em>m</em><em>/</em><em>h</em><em> </em><em>,</em><em> </em><em>means</em><em> </em><em>if</em><em> </em><em>the</em><em> </em><em>car</em><em> </em><em>runs</em><em> </em><em>constantly</em><em> </em><em>at</em><em> </em><em>this</em><em> </em><em>speed</em><em> </em><em>then</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>cover</em><em> </em><em>8</em><em>0</em><em> </em><em>kilometres</em><em> </em><em>in</em><em> </em><em>1</em><em> </em><em>hour</em><em>.</em><em> </em>

<em>.</em><em> </em>

<em>.</em><em> </em>

<em>.</em>

{\bold{\red{HOPE\:IT\:HELPS!}}}

\color{yellow}\boxed{\colorbox{black}{MARK\: BRAINLIEST!❤}}

4 0
2 years ago
an object weighs 98 n on earth. How much does it weigh on planet x where the acceleration due to gravity in 6 m/s^2
Degger [83]
60 N because 98N=mg (here g= 9.8 on earth) thus mass can be calculated which is 98/9.8 = 10kg Now,new weight with g = 6m/s^2 =m×g' (here g' is new acceleration of the new planet) = 10×6=60N
7 0
3 years ago
Read 2 more answers
If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?
leva [86]

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

<span>[density * volume]_salt water = [density * volume]_fresh water                 ---> 1</span>

 

First we calculate the amount of volume displaced in the harbour (salt water):

V = 3.0 m * 20.0 m * 0.70 m

V = 42 m^3 of salt water

Plugging in the values into equation 1:

1029 kg / m^3 * 42 m^3 = 1000 kg/m^3 * Volume fresh water

Volume fresh water displaced = 43.218 m^3

 

Therefore the depth of the barge in the river is:

43.218 m^3 = 3.0 m * 20.0 m * h

<span>h = 0.72 m        (ANSWER)</span>

8 0
3 years ago
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