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scZoUnD [109]
3 years ago
10

. Find the buoyant force exerted on a ball with radius of 2 meters, when the ball is entirely immersed in the water.

Physics
1 answer:
almond37 [142]3 years ago
8 0

Explanation:

Buoyancy force is equal to the weight of the displaced fluid:

B = ρVg

where ρ is the density of the fluid,

V is the volume of the displaced fluid,

and g is the acceleration due to gravity.

The fluid is water, so ρ = 1000 kg/m³.

The volume displaced is that of a sphere with radius 2 m:

V = 4/3 π r³

V = 4/3 π (2 m)³

V ≈ 33.5 m³

The buoyancy force is therefore:

B = (1000 kg/m³) (33.5 m³) (9.8 m/s²)

B ≈ 328,400 N

Round as needed.

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As a child walks, for a brief moment his entire weight is placed on one heel, which can be approximated as a small circle. Calcu
Brut [27]

The correct answer is option b, 63.6 kPa

Given,

The diameter of the heel, d=7 cm=0.07 m

The mass of the child, m=25 kg

The pressure is given by the ratio of the force to the area through which the force is applied.

The force applied on the floor by the child is equal to its weight.

Thus the pressure applied on the floor by the child is given by,

\begin{gathered} P=\frac{F}{A} \\ =\frac{mg}{\pi(\frac{d}{2})^2} \end{gathered}

Where A is the area of the cross-section of the heel.

On substituting the known values,

\begin{gathered} P=\frac{25\times9.8}{\pi(\frac{0.07}{2})^2} \\ =63.6\times10^3\text{ Pa} \\ =63.6\text{ kPa} \end{gathered}

Thus the pressure applied on the floor by the heel is 63.6 kPa

4 0
1 year ago
How much energy must be absorbed by water with a mass of 0.5 kg in order to raise the temperature from 30°C to 65°C? Note: Water
kvasek [131]

Answer:

73325J

Explanation:

Given parameters:

Mass of water  = 0.5kg

Initial temperature  = 30°C

Final temperature  = 65°C

Specific heat capacity  = 4190J/kg°C

Unknown:

Amount of energy absorbed = ?

Solution:

The amount of energy absorbed can be derived using the expression below;

                H  = m c Δt

H is the amount of energy

m is the mass

c is the specific heat

Δt is the change in temperature

      H  = 0.5 x 4190 x (65 - 30 )

     H  = 73325J

6 0
3 years ago
An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to
Lana71 [14]

complete question:

An observer at the top of a 462-ft cliff measures the angle of depression from the top of the cliff to a point on the ground to be 5°. What is the distance from the base of the cliff to the point on the ground? Round to the nearest foot

Answer:

a ≈  5281 ft

Explanation:

The observer at the top of a 462 ft cliff  measures the angle of depression from the top of the cliff to a point on the ground to be 5°.

The angle of depression form the top of the cliff = 5°

The 5° is outside the triangle formed . To find the angle in the triangle we have to subtract 5° from 90°.  90° - 5° = 85° Note sum of an angle on a right angle is 90°.  

using SOHCAHTOA  principle we can solve for the distance from the base of the cliff to the point on the ground(a)

tan  85° = opposite / adjacent

tan 85°  = a / 462

cross multiply

462 × tan 85° = a

a = 11.4300523 × 462

a =  5280.66  ft

a ≈  5281 ft

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