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scZoUnD [109]
3 years ago
10

. Find the buoyant force exerted on a ball with radius of 2 meters, when the ball is entirely immersed in the water.

Physics
1 answer:
almond37 [142]3 years ago
8 0

Explanation:

Buoyancy force is equal to the weight of the displaced fluid:

B = ρVg

where ρ is the density of the fluid,

V is the volume of the displaced fluid,

and g is the acceleration due to gravity.

The fluid is water, so ρ = 1000 kg/m³.

The volume displaced is that of a sphere with radius 2 m:

V = 4/3 π r³

V = 4/3 π (2 m)³

V ≈ 33.5 m³

The buoyancy force is therefore:

B = (1000 kg/m³) (33.5 m³) (9.8 m/s²)

B ≈ 328,400 N

Round as needed.

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A firecracker breaks up into two pieces, one of which has a mass of 200 g and flies off along the x-axis with a speed of 82.0 m/
larisa [96]

Answer:

Total momentum, p = 21.24 kg-m/s

Explanation:

Given that,

Mass of first piece, m_1=200\ g= 0.2\ kg

Mass of the second piece, m_2=300\ g= 0.3\ kg

Speed of the first piece, v_1=82\ m/s (along x axis)

Speed of the second piece, v_2=45\ m/s (along y axis)

To find,

The total momentum of the two pieces.

Solve,

The total momentum of two pieces is equal to the sum of momentum along x axis and along y axis.

p_x=m_1v_1

p_x=0.2\ kg\times 82\ m/s

p_x=16.4\ kg-m/s

p_y=m_2v_2

p_y=0.3\ kg\times 45\ m/s

p_y=13.5\ kg-m/s

The net momentum is given by :

p=\sqrt{p_x^2+p_y^2}

p=\sqrt{16.4^2+13.5^2}

p = 21.24 kg-m/s

Therefore, the total momentum of the two pieces is 21.24 kg-m/s.

4 0
2 years ago
Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1150 kg and was approaching at
devlian [24]
Force acting during collision is internal so momentum is conserve so (initial momentum = final momentum) in both directions Two cars collide at an icy intersection and stick together afterward. The first car has a mass of 1150 kg and was approaching at 5.00 m/s due south. The second car has a mass of 750 kg and was approaching at 25.0 m/s due west. Let Vx is and Vy are final velocities of car in +x and +y direction respectively. initial momentum in +ve x (east) direction = final momentum in +ve x direction (east)

- 750*25 + 1150*0 = (750+1150)
Vx initial momentum in +ve y (north) direction = final momentum in +ve y direction (north)

750*0 - 1150*5 = (750+1150)
Vy from here you can calculate Vx and Vy so final velocity V is


<span>V=<span>(√</span><span>V2x</span>+<span>V2y</span>) 
</span>
and angle make from +ve x axis is

<span>θ=<span>tan<span>−1</span></span>(<span><span>Vy</span><span>Vx</span></span>)

</span><span> kinetic energy loss in the collision = final KE - initial KE</span>
5 0
3 years ago
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What power of an engine is required to pump 2450N of water per second from a well 50m deep to the surface
Arisa [49]
The correct one is A
4 0
3 years ago
Jupiter's satellite Europa orbits Jupiter with a period of 3.55 d at an orbital radius of 6.71 108 m (assume the orbit to be cir
yawa3891 [41]

Answer:

(a)

M = 1.898 x 10^27 kg

(b)

v = 13.74 km/s

(c) E = 0.28 N/kg

Explanation:

Time period, T = 3.55 days = 3.55 x 24 x 3600 second = 306720 s

Radius, r = 6.71 x 10^8 m

G = 6.67 x 10^-11 Nm^2/kg^2

(a) T=2\pi \sqrt{\frac{r^{3}}{GM}}

M=\frac{4\pi ^{2}r^{3}}{GT^{2}}

M=\frac{4\times3.14^{2}\times 6.71^{3}\times 10^{24}}{6.67\times 10^{-11}\times 306720^{2}}

M = 1.898 x 10^27 kg

(b) Let v be the orbital velocity

v=\frac{2\pi r}{T}

v=\frac{2\times 3.14\times 6.71\times 10^{8}}{306720}

v = 13739.5 m/s

v = 13.74 km/s

(b) The gravitational field E is given by

E = \frac{GM}{r^{2}}

E = \frac{6.67\times10^{-11}\times 1.898\times 10^{27}}{6.71^{2}\times 10^{16}}

E = 0.28 N/kg

6 0
2 years ago
A plane opens a parachute after it lands inorder to
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Answer:

When the parachute opens, the air resistance increases. The skydiver slows down until a new, lower terminal velocity is reached.

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