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wlad13 [49]
3 years ago
11

A point charge of 6.8 C moves at 6.5 × 104 m/s at an angle of 15° to a magnetic field that has a field strength of 1.4 T. What i

s the magnitude of the magnetic force acting on the charge? 1.6 × 10–1 N 6.0 × 10–1 N 1.6 × 105 N 6.0 × 105 N
(please show your work in solving this)
Physics
2 answers:
Tamiku [17]3 years ago
6 0

Force on a moving charge is given by

F = q(v x B)

Given that

q = 6.8 C

v = 6.5 * 10^4 m/s

B = 1.4 T

angle = 15 degree

F = qvB sin\theta

F = 6.8*6.5 * 10^4 * 1.4 * sin15

F = 1.6 * 10^5 N

Mrac [35]3 years ago
6 0

Answer:

A

Explanation:

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