Answer:
<h2>
187,500N/m</h2>
Explanation:
From the question, the kinectic energy of the train will be equal to the energy stored in the spring.
Kinetic energy = 1/2 mv² and energy stored in a spring E = 1/2 ke².
Equating both we will have;
1/2 mv² = 1/2ke²
mv² = ke²
m is the mass of the train
v is the velocity of then train
k is the spring constant
e is the extension caused by the spring.
Given m = 30000kg, v = 4 m/s, e = 4 - 2.4 = 1.6m
Substituting this values into the formula will give;
30000*4² = k*1.6²
The value of the spring constant is 187,500N/m
Answer:
<h2>line B</h2>
Explanation:
According to ohm's law V = IR where;
V i sthe supply voltage (in volts)
I = supply current (in amperes)
R = resistance (in ohms)
In order to calculate the line that is equal to 2ohms, we need to calculate the slope of each line using the formula.
For line B, R = ΔV/ΔI
R = V₂-V₁/I₂-I₁
R = 14.0-4.0/7.0-2.0
R = 10.0/5.0
R = 2.0ohms
Since the slope of line B is equal to 2 ohms, this shows that the line B is the one that represents the 2ohms resistor.
Answer:
1. 230 kg...
W = m * g
W= 230 kg * 9.81 m/s^2
<u>W= 2256,3 N</u>
m= 230kg , W = 2256,3 N , g= 9.81 m/s^2
2. 887 N
W= m * g
887 N = m * 9.81 m/s^2
<u>m= 90,42 kg</u>
m= 90,42 kg, W = 887 N , g= 9.81 m/s^2
3. 420 kg
W= m * a
w= 420 kg * 9.81 m/s^2
<u>w=</u><u> </u><u>4120,2 N</u>
m= 420 kg , W = 4120,2 N , g= 9.81 m/s^2
4. Determine the gravity on Pluto where a 15 kg object weighs 55.5N.
w = m * g
55.5 N = 15 kg * g
<u>a= 3,7 m/s^2</u>
m = 15 kg , W= 55.5 N , g= 3,7 m/s^2
