Answer:
The tires of a car support the weight of a stationary car. If one tire has a slow leak, the air pressure within the tire will decrease with time, the surface area between the tire and the road will increase with time, and the net force the tire exerts on the road will be constant with time.
Explanation:
when a wheel has an air leak, it means that the inside of the tire has less air, which means that there will be less air pushing the walls of the tire so that the air pressure decreases.
On the other hand, the tire begins to deform due to lack of air which increases the area of contact with the floor.
As the weight of the car remains constant and the air has a negligible mass the force towards the road will be the same
Answer:
0.09 m/s²
Explanation:
Acceleration: This can be defined as the rate of change of velocity.
The S.I unit of acceleration is m/s².
From the question, expression for acceleration is given as
F' = ma
Using Pythagoras Theory,
√(F₁²+F₂²) = ma................... Equation 1
Where F₁ = Force of the First person on the boulder, F₂ = Force of the Second person on the boulder, F' = resultant force acting on the boulder, m = mass of the boulder, a = acceleration of the boulder.
make a the subject of the equation
a = √(F₁²+F₂²) /m................ Equation 2
Given: m = 825 kg, F₁ = 64 N, F₂ = 38 N,
Substitute into equation 2
a = [√(64²+38²)]/825
a = {√(5540)}/825
a = 74.43/825
a = 0.09 m/s²
Softball weigh around 180 grams or that would be 0.18 Kg. Basketball usually weighs around 22 ounce or 0.6 Kg. To compare the momentum of the two ball we have to use the formula of momentum which is p = mv. m for mass and v for velocity. let us assume both ball are travelling 2 m/s).
Softball. p = mv = (0.18 Kg)(2 m/s) = 0.36 Kg.m/s ( smaller momentum)
Basketball p = mv = (0.6 Kg)(2 m/s) = 1. 2 Kg.m/s (larger momentum
Answer:
The average acceleration of the rocket, a = 8.5 m/s²
Explanation:
Given that,
The upward force of the rocket, F = 1700 N
The time duration of rocket exerted the force, t = 8 s
The mass of the rocket, m = 200 Kg
The force exerted by the rocket is equal to the product of its mass and acceleration.
Therefore, the formula for force
<em> F = m x a</em>
a = F / m
Substituting the given values in the above equation
a = 1700 N / 200 Kg
= 8.5 m/s²
Hence, the acceleration of the rocket is, a = 8.5 m/s²
