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LiRa [457]
3 years ago
12

A barbel weighing 215N is raised to a height of 2.0 M above the ground. It is then dropped from that height.

Physics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

  • 430 J
  • 6.26 m/s

Explanation:

A. The kinetic energy is the same as the initial potential energy:

  PE = mgh = (215 N)(2.0 M) = 430 J

__

B. The velocity achieved by falling from a height h is given by ...

  v = √(2gh)

  v =  √(2·9.8 m/s^2·2 m) = √(39.2 m^2/s^2)

  v ≈ 6.26 m/s

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2 Points<br> How did J. J. Thomson change the atomic model based on his experimental<br> results?
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Explanation:

In 1897, J.J. ... Thomson realized that the accepted model of an atom did not account for negatively or positively charged particles. Therefore, he proposed a model of the atom which he likened to plum pudding. The negative electrons represented the raisins in the pudding and the dough contained the positive charge.

6 0
4 years ago
An elevator cab has a mass of 4710 kg and can carry a maximum load of 1910 kg. If the cab is moving upward at full load at 3.80
OLEGan [10]

Answer:

Power P=246.78 KW

Explanation:

Mass of Elevator=4710 Kg

Can carry load =1910 Kg

Total Mass m to be lifted =4710 kg + 1910 Kg =6620 kg

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Using formula of Power P = \frac{work}{time}

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4 0
3 years ago
Discuss why Wolpert says we have a brain.
ycow [4]

Answer:

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8 0
3 years ago
Read 2 more answers
A 1,550 kg car moving south at 10.0 m/s collides with a 2,550 kg car moving north. The cars stick together and move as a unit af
nikitadnepr [17]

Answer:

14.47 m/s

Explanation:

The momentum must be preserved before and after the collision:

The total momentum before the collision

m_1v_1 + m_2v_2

where m_1 = 1550 kg, m_2 = 2550 kg are the masses of the car moving south and north, respectively, before the collision. v_1 = -10m/s is the velocity of the car moving South. We take the velocity to the North as the positive direction

The total momentum after the collision

(m_1 + m_2)V

where V = 5.22m/s is the velocity of both cars after the collision

We can equalize the 2 equations and plug in the numbers:

m_1v_1 + m_2v_2 = (m_1 + m_2)V

1550(-10) + 2550*v_2 = (1550 + 2550)5.22

-15500 + 2550v_2 = 21402

2550v_2 = 36902

v_2 = 36902/2550 = 14.47 m/s

6 0
3 years ago
Many objects orbit the sun in the Kuiper belt. should such an object be called a comet if it does not have a tail? develop an ar
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