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LiRa [457]
3 years ago
12

A barbel weighing 215N is raised to a height of 2.0 M above the ground. It is then dropped from that height.

Physics
1 answer:
aleksandrvk [35]3 years ago
8 0

Answer:

  • 430 J
  • 6.26 m/s

Explanation:

A. The kinetic energy is the same as the initial potential energy:

  PE = mgh = (215 N)(2.0 M) = 430 J

__

B. The velocity achieved by falling from a height h is given by ...

  v = √(2gh)

  v =  √(2·9.8 m/s^2·2 m) = √(39.2 m^2/s^2)

  v ≈ 6.26 m/s

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A rotating viscometer consists of two concentric cylinders –an inner cylinder of radius Rirotating at angular velocity (rotation
RSB [31]

Answer:

b)  the result we got can be termed approximation because we are neglecting the shear stress acting on the two ends of the cylinder. Here we have considered only the share stress acting on the curved surface area only.

Explanation:

check attachment for solution to A

4 0
3 years ago
A pulse of red light and a pulse of blue light enter a glass block normal to its surface at the same time. after passing through
pshichka [43]
I believe the red light would go faster than the blue.
7 0
3 years ago
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A lead bar 12 cm long, 2 cm wide, and 2 cm talk has a density of 11.3g/cm3. If you cut the bar in half, what is the density of o
VMariaS [17]

Answer:

The density of one halves  11.3 g / cm cube

Explanation:

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density = \frac{mass}{volume}

5 0
3 years ago
Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms.
yulyashka [42]

The vertical height from where Jeff dropped the bottle is 10m.

<h3>What is free falling?</h3>

When an object is released from rest in free air considering no friction, the motion is depend only on the acceleration due to gravity, g.

If we drop an object of mass m near the Earth surface from a height h, it has initial mechanical energy(P.E) of

U =mgh

When the object strikes the ground, all the potential energy converted into kinetic energy.

k.E = 1/2mv²

where v is the speed just before hitting the ground.

From energy conservation principle, initial and final mechanical energy are equal.

mgh = 1/2mv²

Given is Jeff climbs a hill. He drops his water bottle, which has a mass of 0.25 kilograms. The bottle slides down the hill and is moving at a velocity of 14 meters/second the instant it hits the ground.

The height from which bottle could fall is

h = v²/2g

Substitute the values, we get

h = (14)²/(2x9.81)

h =9.99 m

Thus,  vertical height from where Jeff dropped the bottle is approximately  10m.

Learn more about free falling.

brainly.com/question/13299152

#SPJ1

8 0
1 year ago
two people, each with a mass of 70 kg, are wearing inline skates and are holding opposite ends of a 15m rope. One person pulls f
Zina [86]

Answer:

7.75 s

Explanation:

Newton's second law:

∑F = ma

35 N = (70 kg) a

a = 0.5 m/s²

Given v₀ = 0 m/s and Δx = 15 m:

Δx = v₀ t + ½ at²

(15 m) = (0 m/s) t + ½ (0.5 m/s²) t²

t = 7.75 s

5 0
3 years ago
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