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3 years ago

A solution is made by mixing 31 g of heptane C7H16 and 42 g of chloroform CHCl3.

Chemistry

2 answers:

levacccp [35]3 years ago

8 0

Answer:

The mol fraction of heptane in this solution is 0.47

Explanation:

Step 1: Data given

Mass of heptane = 31.00 grams

Molar mass of heptane = 100.21 g/mol

Mass of chloroform = 42.00 grams

Molar mass of chloroform = 119.38 g/mol

Step 2: Calculate moles heptane

moles heptane = 31.00 grams / 100.21 g/mol

moles heptane = 0.309 moles

Step 3: Calculate moles chloroform

moles chloroform = 42.00 grams / 119.38 g/mol

moles chloroform = 0.352 moles

Step 4: Calculate total moles

Total moles = moles heptane + moles chloroform

Total moles = 0.309 moles + 0.352 moles = 0,661 moles

Step 5: Calculate mol fraction of heptane

Mol fraction heptane = moles heptane / total moles

Mol fraction heptane = 0.309 moles / 0.661 moles

Mol fraction heptane = 0.47

The mol fraction of heptane in this solution is 0.47

marishachu [46]3 years ago

8 0

Answer:

Mole fraction heptane is 0.47

Explanation:

To calculate the mole fraction, let's convert mass to mol

Mass / Molar mass = Mol

Molar mass heptane = 100 g/m

31 g/100 g/m = 0.31 moles

Molar mass chloroform = 119.35 g/m

42 g / 119.35 g/m = 0.351 moles

Total moles = 0.31 + 0.351 = 0.661 moles

Moles of heptane / Total moles = Mole fraction

0.31 / 0.661 = 0.47

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