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Irina18 [472]
3 years ago
14

A solution is made by mixing 31 g of heptane C7H16 and 42 g of chloroform CHCl3.

Chemistry
2 answers:
levacccp [35]3 years ago
8 0

Answer:

The mol fraction of heptane in this solution is 0.47

Explanation:

Step 1: Data given

Mass of heptane = 31.00 grams

Molar mass of heptane = 100.21 g/mol

Mass of chloroform = 42.00 grams

Molar mass of chloroform = 119.38 g/mol

Step 2: Calculate moles heptane

moles heptane = 31.00 grams / 100.21 g/mol

moles heptane = 0.309 moles

Step 3: Calculate moles chloroform

moles chloroform = 42.00 grams / 119.38 g/mol

moles chloroform = 0.352 moles

Step 4: Calculate total moles

Total moles = moles heptane + moles chloroform

Total moles = 0.309 moles + 0.352 moles = 0,661 moles

Step 5: Calculate mol fraction of heptane

Mol fraction heptane = moles heptane / total moles

Mol fraction heptane = 0.309 moles / 0.661 moles

Mol fraction heptane = 0.47

The mol fraction of heptane in this solution is 0.47

marishachu [46]3 years ago
8 0

Answer:

Mole fraction heptane is 0.47

Explanation:

To calculate the mole fraction, let's convert mass to mol

Mass / Molar mass = Mol

Molar mass heptane = 100 g/m

31 g/100 g/m = 0.31 moles

Molar mass chloroform = 119.35 g/m

42 g / 119.35 g/m = 0.351 moles

Total moles = 0.31 + 0.351 = 0.661 moles

Moles of heptane / Total moles = Mole fraction

0.31 / 0.661 = 0.47

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Question 1:

The diagram for gallium will have flat, horizontal lines at <u><em>30 and 2204</em></u><em> </em>°C.

Questoin 2:

The diagram for methane will have a <u><em>diagonal </em></u>line representing the <u><em>liquid phase</em></u> between -183°C and -162°C.

Question 3:

For gold, the boiling point corresponds to the y-value at <u><em>2856</em></u><u> </u>°C of <u><em>the top horizontal line</em></u>

Question 4.

For nitrogen, the line at -210°C will be<u><em> flat</em></u>, which represents <u><em>the change from a solid to a liquid</em></u>

Explanations:

Question 1:

The diagram for gallium will have flat, horizontal lines at <u><em>30 and 2204</em></u><em> </em>°C.

The table shows that the melting point of gallium is 30°C and its boiling point is 2204°C.

<em>Melting point</em> is the temperature at which the substace changes its state from<em> solid to liquid</em>. During that change, <em>the temperature</em> of the substance <em>does not change</em>, because the heat supplied is used to accomplish the phase change. So, the temperature is constant and that means <em>that portion of the diagram is flat</em>.

The same is valid during<em> boiling</em>: the temperature remains constant while the substance is passing<em> from liquid to gas</em> at the boiling point.

Questoin 2:

The diagram for methane will have a <u><em>diagonal </em></u>line representing the <u><em>liquid phase</em></u> between -183°C and -162°C.

Between the <em>melting</em> (-183°C) and<em> boiling</em> (-162°C) points of methane, its temperature will increase more or less linearly, which is represented with a <em>diagonal</em> (slant) <em>line</em> between those points. During this interval the heat is used to <em>increase the temperature</em> and no phase of change happens.

Question 3:

For gold, the boiling point corresponds to the y-value at <u><em>2856</em></u><u> </u>°C of <u><em>the top horizontal line</em></u>

<u><em></em></u>

The table shows that the<em> boiling point</em> of gold is 2,856°C.

In a <em>temperature-vs.-time diagram</em> the<em> temperature is represented on the vertical axis (y-value)</em> and the time is represented on the horizontal axis.

Since, the temperature of the substance does not change during <em>boiling,</em> the line during the time that this change of phase is happening is flat. And since this temperatue is higher than the melting temperature, this is the <em>top horizontal line in the diagram</em>.

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<u><em></em></u>

The table shows that the <em>melting point </em>of nitrogen is -210°C, that means that the temperature will remain constant at -210°C while the substance is absorbing heat to pass from solid to liquid.

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