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tamaranim1 [39]
3 years ago
5

`If you had one test tube containing aqueous AgNO3 and another one containing NH4Cl, and you poured them together into a beaker,

what would be the formula of the precipitate that forms?
Chemistry
1 answer:
coldgirl [10]3 years ago
4 0

Answer:

AgCl

Explanation:

The reaction is AgNO3 (aq) + NH4Cl --------->AgCl(s) + NH4NO3.

Silver chloride is an insoluble salt that will precipitate out of the reaction mixture. It can then the filtered off, washed and dried.

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Use the oxidation rule to determine the oxidation number of carbon in H2CO3
torisob [31]
In sure u will do great and the answer will be right
3 0
3 years ago
Make a prediction about the relationship between electrons and molecular shapes ​
Oksana_A [137]

Answer:

★ Molecular geometry is described by VSEPR theory, which basically states that electron pairs around a central atom will repel each other, and get as far apart as possible, in three dimensions.

Explanation:

Hope you have a great day :)

6 0
2 years ago
A sample of 8.11 g 8.11 g of solid calcium hydroxide is added to 38.0 mL 38.0 mL of 0.410 M 0.410 M aqueous hydrochloric acid. W
Andrews [41]

Answer:

The balanced chemical equation :

Ca(OH)_2(s)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)

Explanation:

When calcium hydroxide reacts with hydrochloric acid it gives calcium chloride and water as a products. The chemical equation is given as:

Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O

According to question, solid calcium hydroxde is added to 38.0 mL of 0.410 M of HCl solution, so the chemical equation can be written as:

Ca(OH)_2(s)+2HCl(aq)\rightarrow CaCl_2(aq)+2H_2O(l)

According to stoichiometry, when 1 mole of solid calcium hydroxide reacts with 1 mole of hydrochloric acid to gives 1 mole of aqueous calcium chloride and 1 mole of water.

4 0
3 years ago
About 6 × 109 g of gold is thought to be dissolved in the oceans of the world. If the total volume of the oceans is 1.5 × 1021 L
Lelechka [254]

First, determine the number of moles of gold.

Number of moles  = \frac{given mass in g}{molar mass}

Given mass of gold  =6 \times 10^{9} g

Molar mass of gold  = 196.97 g/mol

Put the values,

Number of moles of gold  = \frac{6 \times 10^{9} g}{196.97 g/mol}

= 0.03046\times  10^{9} mole or 3.046\times  10^{7} moles

Now, molarity  = \frac{moles of solute}{volume of the solution in liters}

Put the values, volume of ocean  =1.5 \times 10^{21} L

Molarity = \frac{3.046\times 10^{7} moles}{1.5 \times 10^{21} L}

= 2.03\times 10^{-14} M

Thus, average molar concentration = 2.03\times 10^{-14} M




6 0
3 years ago
Convert 45.5 mmHg into kPa
Karolina [17]

Answer:

for anapproximate result , divide the pressure value by 7.501

8 0
3 years ago
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