Answer:
θ = 25.4º
Explanation:
For this exercise we can use the projectile launch equations, let's use the scope ratio
R = vo² sin 2θ / g
For the first ball
R1 = 35² 2 sin (2 30) /9.8
R1 = 108.25 m
For the second ball, they ask that the second ball fall in the same place, so the horizontal distance is the same
R2 = R1
Therefore we calculate the angle
sin 2θ = R1 g / vo²
sin 2θ = 108.25 9.8 / 37²
sin 2θ = 0.7749
2θ = sin⁻¹ (0.7749)
2θ = 50.8º
θ = 25.4º
Answer:
C
Explanation:
got a one hundred on the test
Answer:
The total frictional force is 358.0 newtons
Explanation:
Power is the amount of average work (W) an object does on a period of time (Δt):
Remember average work is average force (F) times displacement (Δs):
but displacement over time is average speed , then:
(1)
That is, the power of the car is the force the engine does times the speed of the car. As the question states, if the car is at constant velocity then the power developed is used to overcome the frictional forces exerted by the air and the road, that is by Newton's first law, the force the motor of the car does is equal the force of frictional forces. So, to find the frictional forces we only have to solve (1) for F:
Knowing that 1hp is 746W then 30hp=22380W and 1 mile = 1609m then 140 mph = 225308 = , then:
Answer:
A kg of cotton is heavier.
Explanation:
Because in air, cotton gets upthrust that's why weighing machine gives less weight than its actually have.
for eg: If cotton has 800g weight, the machine shows a kg(1kg) when measure in air due to upthrust.
I hope this will be helpful for you.