The storage method used for radioactive wastes generated from fission nuclear reactors must be designed to last for how long?
2 answers:
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Answer:
The value of total energy needed per minute for the humidifier = 77.78 KJ
Explanation:
Total energy per minute the humidifier required = Energy required to heat water to boiling point) + Energy required to convert liquid water into vapor at the boiling point) ----- (1)
Specific heat of water = 4190
The heat of vaporization is = 2256
Mass = 0.030 kg
Energy needed to heat water to boiling point =
Energy needed to heat water to boiling point = 0.030 × 4.19 × (100 - 20)
Energy () = 10.08 KJ
Energy needed to convert liquid water into vapor at the boiling point
= 0.030 × 2256 = 67.68 KJ
Thus the total energy needed E = +
E = 10.08 + 67.68
E = 77.78 KJ
This is the value of total energy needed per minute for the humidifier.
To calculate and solve the problem it is necessary to apply the concepts related to resistance and resistivity.
The equation that is responsible for relating the two variables is:
Where,
R= Resistance of the conductor
Resistivity of the conductor material
L = Length
A = Cross-sectional area of conductor
With the previous values the area of the muscle (Real Muscle-82%)is,
Using the equation from Resistance we have that at the muscle the value is:
At the same time we can make the same process to calculate the resistance of the fat, then
The resistance of the fat would be,
Then the total resistance in a set as the previously writen, i.e, in parallel is:
We can here apply Ohm's law, then