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Butoxors [25]
3 years ago
6

a meteoroid changed velocity from 1.0km/s to 1.8 km/s in 0.03 seconds. what is the acceleration of the meteoroid

Physics
1 answer:
Greeley [361]3 years ago
5 0
A meteoroid changed velocity from 1.0 km/s to 1.8 km/s in 0.03 seconds.
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An object moves in uniform circular motion at 25 m/s and takes 1.0 second to go a quarter circle. Calculate the centripetal acce
tekilochka [14]

Given:

Object in circular motion 25 m/s

1 second to go quarter circle

Required:

Centripetal acceleration:

Solution:

Acceleration = v2/r

Where v is the velocity and r is the radian

Substituting the values into the equation,

Acceleration = v2/r = (25 m/s)2/(4*pi/180) = 8952.47 m2/s2

4 0
4 years ago
An antiproton is identical to a proton except it has the opposite charge, −e. To study antiprotons, they must be confined in a
Zigmanuir [339]

Answer:

Explanation:

We know that, the force responsible for circulating in circular path is the centripetal force given by the force on charged particle due to magnetic field.

Here the charge is antiproton is

p = -1.6 * 10⁻¹⁹C

the speed of proton is given by 1.5 * 10 ⁴ m/s

the magnetic field is B = 4.5 * 10⁻³T

we have force due to magnetic field is equal to centripetal force

Bqv = mv² / r

Bq = mv / r

r = \frac{mv}{Bq} \\\\r=\frac{mv}{Bq} \\\\r=\frac{1.67 \times 10^-^2^7\times 1.5 \times 10^4}{4.5 \times 10^-^3\times 11.6\times 10^-^1^9} \\\\r=347.9\times 10^-^4\\\\r=3.479cm

The diameter d of the vacuum chamber have to allow these antiprotons to circulate without touching the walls is

d = 2r

d = 2 * 3.479

d = 6.958

d ≅ 7cm

7 0
4 years ago
Two objects of the same radius start from rest and roll without slipping down a ramp. The objects are a hollow cylinder and a so
Westkost [7]

Answer:

Solid cylinder

Explanation:

because hollow may blow and just bounce

8 0
3 years ago
A train is traveling away from you at 120 km/h. it blows its whistle, and you hear a tone of 0.400 kHz. Take the speed of sound
Vaselesa [24]

Answer:B)439.21 Hz

Explanation:

Given

velocity of train v=120 km/h\approx 120\times \frac{5}{18}=33.33 m/s

frequency of train f_a=0.400 kHz\approx 400 Hz

speed of sound c=340 m/s

frequency from Doppler effect can be calculated by

f_a=(\frac{c}{c+v})\cdot f

400=(\frac{340}{340+33.33})\cdot f

400=\frac{340}{373.33}\cdot f

f=400\times 1.098

f=439.21 Hz

5 0
3 years ago
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