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kirill115 [55]
3 years ago
13

How many molecules are in 10.0 miles of C2H6O

Chemistry
1 answer:
shutvik [7]3 years ago
3 0
6.02 x 10²⁴ molecules of C2H6O
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1. The emission spectrum of mercury atoms has a bright green line with wavelength
SashulF [63]

Emission spectrum results from the movement of an electron from a higher to a lower energy level. The frequency of the photon is 5.5 * 10^14 Hz.

From the formula;

E = hc/λ

h = Plank's constant =6.6 * 10^-34 Js

c = speed of light=  3 * 10^8

λ = wavelength = 546.1 * 10^-9 m

E =  6.6 * 10^-34 * 3 * 10^8/546.1 * 10^-9

E =3.63 * 10^-19 J

Also;

E =hf

Where;

h = Planks's constant

f = frequency of photon

f = E/h

f = 3.63 * 10^-19 J/6.6 * 10^-34

f = 5.5 * 10^14 Hz

Learn more: brainly.com/question/18415575

5 0
3 years ago
In the simple act of lighting a match, chemical energy stored in the match head is transformed into heat and light. What is true
harina [27]

The head of a matchstick has a great deal of chemical energy stored in it, including combustible substances that produce a flame when rubbed against a suitable surface. ... As the combustible materials burn, some of the chemical energy is transformed into heat energy, and some is transformed into light energy. Hope this helps

5 0
3 years ago
Read 2 more answers
Complete combustion of 5.90 g of a hydrocarbon produced 19.2 g of CO2 and 5.89 g of H2O. What is the empirical formula for the h
scZoUnD [109]
44g \ CO_{2} \ \ \ \rightarrow \ \ 12g \ C\\
19,2g \ CO_{2} \rightarrow \ \ \ x\\\\
x=\frac{19,2g*12g}{44g}\approx5,24g \ \ \ \Rightarrow \ \ n=\frac{5,24g}{12\frac{g}{mol}}\approx0,44mol\\\\\\
18g \ H_{2}O \ \ \ \rightarrow \ \ \ 2g \ H\\
5,89g \ H_{2}O \ \rightarrow \ \ y\\\\
y=\frac{5,89g*2g}{18g}\approx0,65g \ \ \ \ \Rightarrow \ \ n=\frac{0,65g}{1\frac{g}{mol}}=0,65mol\\\\\\
n_{C}:n_{H}=0,44:0,65\approx1:1\\\\
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4 0
3 years ago
How many mL of a 1.48 M calcium hydroxide solution are needed to neutralize 36.0 mL of a 1.63 M hydrochloric acid solution
Lelechka [254]

The volume (in mL) of calcium hydroxide, Ca(OH)₂ needed for the reaction is 19.8 mL

<h3>Balanced equation </h3>

2HCl + Ca(OH)₂ —> CaCl₂ + 2H₂O

From the balanced equation above,

  • The mole ratio of the acid, HCl (nA) = 2
  • The mole ratio of the base, Ca(OH)₂ (nB) = 1

<h3>How to determine the volume of Ca(OH)₂ </h3>
  • Molarity of base, Ca(OH)₂ (Mb) = 1.48 M
  • Volume of acid, HCl (Va) = 36 mL
  • Molarity of acid, HCl (Ma) = 1.63 M
  • Volume of base, Ca(OH)₂ (Vb) =?

MaVa / MbVb = nA / nB

(1.63 × 36) / (1.48 × Vb) = 2

58.68 / (1.48 × Vb) = 2

Cross multiply

2 × 1.48 × Vb = 58.68

2.96 × Vb = 58.68

Divide both side by 2.96

Vb = 58.68 / 2.96

Vb = 19.8 mL

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brainly.com/question/14356286

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6 0
2 years ago
How do weathering and deposition differ?
Paul [167]
C) Weathering can be chemical or physical; deposition
is only chemical
4 0
1 year ago
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