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Tema [17]
3 years ago
7

What is the pH of 0.000134 M solution of HCI?

Chemistry
2 answers:
emmainna [20.7K]3 years ago
7 0

Answer: The pH of 0.000134 M solution of HCl is 3.873.

Explanation:

When HCl dissociates in water then it will give hydrogen and chlorine ions. The reaction will be as follows.

          HCl \rightarrow H^{+} + Cl^{-}

This means that 1 mole of HCl is giving 1 mole of hydrogen ions on dissociation.

Hence, pH of the given solution will be calculated as follows.

                pH = -log [H^{+}]

                      = -log (0.000134)

                      = 3.873

Thus, we can conclude that the pH of 0.000134 M solution of HCl is 3.873.

mafiozo [28]3 years ago
5 0

Answer: The pH will be 3.87

Explanation:

pH or pOH is the measure of acidity or alkalinity of a solution.

pH is calculated by taking negative logarithm of hydrogen ion concentration.

pH=-\log [H^+]

HCl\rightarrow H^++Cl^{-}

According to stoichiometry,

1 mole of HCl gives 1 mole of H^+

Thus 0.000134 moles of HCl gives =\frac{1}{1}\times 0.000134=0.0001342 moles of H^+

Putting in the values:

pH=-\log[0.000134]

pH=3.87

Thus the pH will be 3.87

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Calculate the number of hydrogen atoms present in 40g of urea, (NH2)2CO
tekilochka [14]

Answer: There are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

Explanation:

Given: Mass of urea = 40 g

Number of moles is the mass of substance divided by its molar mass.

First, moles of urea (molar mass = 60 g/mol) are calculated as follows.

Moles = \frac{mass}{molar mass}\\= \frac{40 g}{60 g/mol}\\= 0.67 mol

According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

So, the number of atoms present in 0.67 moles are as follows.

0.67 mol \times 6.022 \times 10^{23} atoms/mol\\= 4.035 \times 10^{23} atoms

In a molecule of urea there are 4 hydrogen atoms. Hence, number of hydrogen atoms present in 40 g of urea is as follows.

4 \times 4.035 \times 10^{23} atoms\\= 16.14 \times 10^{23} atoms

Thus, we can conclude that there are 16.14 \times 10^{23} atoms of hydrogen are present in 40g of urea, (NH_{2})_{2}CO.

7 0
3 years ago
What is the relative formula mass of N2O? Ar of N = 14 and Ar of O = 16.
s2008m [1.1K]

We have to calculate formula mass of N₂O.

The answer is: 44

Relative formula mass is the sum of relative atomic mass of constituent atoms in a formula unit of any compound.  Relative formula mass is represented as same symbol of relative molecular mass.

To calculate relative formula mass we need to know number of each atom in the formula and then adding atomic masses of all the atoms.

In N₂O, number of N-atom present is equal to 2 and number of O-atom is equal to  1.

Atomic mass of N-atom is 14 and atomic mass of O-atom is 16.

So, formula mass of N₂O is (2 X 14)+16 = 44.

6 0
3 years ago
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